1 1 vote Using the incremental low frequency small-signal model of the $\text{MOS}$ device, the Norton equivalent resistance of the following circuit is $r_{ds}+R+g_{m}r_{ds}R \\$ $\dfrac{r_{ds}+R}{1+g_{m}r_{ds}} \\$ $r_{ds}+\dfrac{1}{g_{m}}+R \\$ $r_{ds}+R$ Network Solution Methods gate2020-ec network-solution-methods nortons + – go_editor 750 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
