1 1 vote The current $I$ in the given network is $0 \: A$ $2.38\angle -96.37^{\circ}A$ $2.38\angle143.63^{\circ}A$ $2.38\angle-23.63^{\circ}A$ Network Solution Methods gate2020-ec network-solution-methods + – go_editor 369 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.