Since, This is a linear differential equation of the form: d2y/dx2 + Pdy/dx + Qy = R.
Here P= -6, Q=9, R=0
Now, Converting this in Auxiliary Equation;
m2 - 6m + 9 = 0
m = 3,3
Since, the roots of this eqaution are equal;
Therefore, CF= (C1 + C2x)emx i.e
CF= (C1 + C2x)e3x
and R=0 ; So, PI=0;
Hence, General Solution= CF+PI
i.e general solution = (C1 + C2x)e3x