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Since, This is a linear differential equation of the form: d2y/dx2 + Pdy/dx + Qy = R. 

Here P= -6, Q=9, R=0 

Now, Converting this in Auxiliary Equation; 

           m2 - 6m + 9 = 0

                             m = 3,3

Since, the roots of this eqaution are equal;

Therefore, CF= (C1 + C2x)emx  i.e

                  CF= (C1 + C2x)e3x 

and R=0 ; So, PI=0;

Hence, General Solution= CF+PI

               i.e  general solution =  (C1 + C2x)e3x 

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