1 + $\dfrac{1}{4}$ + $\dfrac{1}{16}$ + $\dfrac{1}{64}$ + $\dfrac{1}{256}$ + ....
By seeing the above series we can identify the series as infinite G.P. series
Here 1st term i.e. a = 1 & common ratio i.e r = $\dfrac{1}{4}$
∴ The sum of the above infinite G.P series will be $\dfrac{1}{1 - \dfrac{1}{4} }$ = $\dfrac{4}{3}$
∴ The answer is option D) $\dfrac{4}{3}$