0 0 votes Let $g(t) = e^{-\pi t^{2}},$ and $h(t)$ is a filter matched to $g(t).$ If $g(t)$ is applied as input to $h(t),$ then the Fourier transformation of the output is $ e^{-\pi f^{2}}$ $ e^{-\pi f^{2}/ 2}$ $ e^{-\pi \mid f \mid }$ $ e^{-2\pi f^{2}}$ Continuous-time Signals gate2013-ec continuous-time-signals fourier-transform + – Milicevic3306 393 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
