Electronis Discussion
0 votes
The voltage of an electromagnetic wave propagating in a coaxial cable with uniform characteristic impedance is $V(l)= e^{-\gamma l +j\omega t }$ Volts, where $l$ is the distance along the length of the cable in meters, $\gamma=(0.1+j40)m^{-1}$  is the complex propagation constant, and $\omega=2 \pi \times 10^{9}$ rad/s is the angular frequency. The absolute value of the attenuation in the cable in dB/meter is__________.
in Electromagnetics by (2.8k points)
retagged by | 60 views

Please log in or register to answer this question.

Welcome to GO Electronics, where you can ask questions and receive answers from other members of the community.
1,174 questions
78 answers
43,964 users