1 1 vote Consider a channel where $x_{n} \in\{0,1\}$ is the input and $y_{n}=x_{n} * z_{n}$ is the output, where $*$ is $\text{EX-OR}$ operation, and $P\left(z_{n}=x_{n-1}\right)=P\left(z_{n}=y_{n-1}\right)=\frac{1}{2}$. Note that communication starts at time $n=0$, and assume $x_{-1}=y_{-1}=0$. Then the capacity of the channel in bits is $\frac{1}{2}.$ $1$. $<1.$ $\geq 0.$ Both $(c)$ and $(d)$. Information Theory tifr2011 information-theory probability-and-statistics + – admin 410 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
