1 1 vote The Fourier transform $X(\omega)$ of $x(t)=e^{-t^{2}}$ is Note: $\int_{-\infty}^{\infty} e^{-y^{2}} d y=\sqrt{\pi}$ $\sqrt{\pi} e^{\frac{\omega^{2}}{2}}$ $\frac{e^{-\frac{\omega^{2}}{4}}}{2 \sqrt{\pi}}$ $\sqrt{\pi} e^{-\frac{\omega^{2}}{4}}$ $\sqrt{\pi} e^{-\frac{\omega^{2}}{2}}$ Continuous-time Signals gateece-2023 fourier-transform continuous-time-signals signals-and-systems + – admin 631 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
