2 2 votes Consider two continuous time signals $x(t)$ and $y(t)$ as shown below If $X(f)$ denotes the Fourier transform of $x(t)$, then the Fourier transform of $y(t)$ is $\_\_\_\_\_\_$. $-4 X(4 f) e^{-j \pi f}$ $-4 X(4 f) e^{-j 4 \pi f}$ $-\frac{1}{4} X(f / 4) e^{-j \pi f}$ $-\frac{1}{4} X(f / 4) e^{-j 4 \pi f}$ Continuous-time Signals gateece-2024 fourier-transform continuous-time-signals + – admin 2.5k views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes B Lucky saini answered Aug 2, 2024 Lucky saini comment Share Follow 0 reply Please log in or register to add a comment.
