2 2 votes Let $\mathbb{R}$ and $\mathbb{R}^{3}$ denote the set of real numbers and the three dimensional vector space over it, respectively. The value of $\alpha$ for which the set of vectors \[ \left\{\left[\begin{array}{lll} 2 & -3 & \alpha \end{array}\right], \quad\left[\begin{array}{lll} 3 & -1 & 3 \end{array}\right], \quad\left[\begin{array}{lll} 1 & -5 & 7 \end{array}\right]\right\} \] does not form a basis of $\mathbb{R}^{3}$ is $\_\_\_\_\_\_\_$. Linear Algebra gateece-2024 numerical-answers linear-algebra vector-analysis + – admin 2.5k views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes 5 Siddharth_IA answered Jul 9, 2024 Siddharth_IA comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes 2-3a3-131-572(-7+15)-3(-21+5a)+1(-9+a)=016+63-15a-9+a=070=14aa=5 rashmi8303 answered Jan 19 rashmi8303 comment Share Follow 0 reply Please log in or register to add a comment.