0 votes 0 votes For a real number $x>1$, \[ \frac{1}{\log _{2} x}+\frac{1}{\log _{3} x}+\frac{1}{\log _{4} x}=1 \] The value of $x$ is $4$ $12$ $24$ $36$ Others gateece-2024 engineering-mathematics algebra numerical-answers + – Arjun asked Feb 16 • edited Feb 27 by makhdoom ghaya Arjun 6.6k points 510 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.