2 2 votes Consider the matrix $A$ below: $$A=\left[\begin{array}{llll} 2 & 3 & 4 & 5 \\ 0 & 6 & 7 & 8 \\ 0 & 0 & \alpha & \beta \\ 0 & 0 & 0 & \gamma \end{array}\right]$$ For which of the following combinations of $\alpha, \beta$, and $\gamma$, is the rank of $A$ at least three? $\alpha=0$ and $\beta=\gamma \neq 0$. $\alpha=\beta=\gamma=0$. $\beta=\gamma=0$ and $\alpha \neq 0$. $\alpha=\beta=\gamma \neq 0$. Only (i), (iii), and (iv) Only (iv) Only (ii) Only (i) and (iii) Linear Algebra gateec-2025 linear-algebra matrices numerical-answers + – Shubham Sharma 2 1.2k views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes The answer is A because to get the rank 3 we need non zero rows . so to get non zero rows 1,3,4 those are possible cases. that's why the option is A . parvathi_jalagam answered Dec 29, 2025 parvathi_jalagam comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes for upper and lower triangular matrices, for the rank to atleast 3 no of non zero diagonal entries have to be equal or more than 3, so either alpha or gama have to be non zero or both can be non zero. so option 1 is correct deekshitha_jaladi answered Jan 26 deekshitha_jaladi comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes A is the answer we have to see the question atleast 3 Alex_rus01 answered Mar 4 Alex_rus01 comment Share Follow 0 reply Please log in or register to add a comment.