2 2 votes A stick of length one meter is broken at two locations at distances of $b_{1}$ and $b_{2}$ from the origin $(0)$, as shown in the figure. Note that $0 < b_{1} < b_{2}<1$. Which one of the following is NOT a necessary condition for forming a triangle using the three pieces? Note: All lengths are in meter. The figure shown is representative. $b_{1}<0.5$ $b_{2}>0.5$ $b_{2} < b_{1} + 0.5$ $b_{1}+b_{2}<1$ Quantitative Aptitude gateec-2025 quantitative-aptitude probability-and-statistics + – Shubham Sharma 2 657 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes For triangle:Largest piece < sum of other twoSince total length = 1, condition becomes:Largest piece < 1/2So all three must be < 0.5b₁ < 0.5 b₂ − b₁ < 0.5 → b₂ < b₁ + 0.51 − b₂ < 0.5 → b₂ > 0.5 b₁ + b₂ < 1 -> This is NOT required for triangle condition.So answer = D. b₁ + b₂ < 1 kp6602 answered Feb 21 kp6602 comment Share Follow 0 reply Please log in or register to add a comment.