Three children $\mathrm{P}, \mathrm{Q}, \mathrm{R}$ and two grown-ups $\mathrm{X}, \mathrm{Y}$ play a badminton doubles tournament. $\text{X}$ and $\text{Y}$ are parents to two of the children playing. The child of $\text{X}$ is not the same as the child of $\text{Y}.$ Exactly one of the children does not have a parent playing in the tournament. The following rules are followed:
- A parent and his/her child cannot be on the same team.
- A match can feature at most one parent and his/her child, that is, a maximum of one parent-child pair can play in a match.
The following matches were played:
\[
\begin{array}{|l|l|l|}
\hline
& \text{TEAM 1} & \text{TEAM 2} \\
\hline
\text{MATCH 1} & P \text{ and } X & Q \text{ and } R \\
\hline
\text{MATCH 2} & P \text{ and } R & X \text{ and } Y \\
\hline
\text{MATCH 3} & R \text{ and } X & Q \text{ and } Y \\
\hline
\end{array}
\]
Which one of the following options is correct?
- P does not have any parent playing
- Q does not have any parent playing
- R does not have any parent playing
- X does not have a child playing
