16 16 votes $S$, $M$, $E$ and $F$ are working in the shifts in a team to finish a project. $M$ works with twice the efficiency of others but for half as many days as $E$ worked. $S$ amd $M$ have $6$ hour shifts in a day, whereas $E$ and $F$ have $12$ hours shifts. What is the ratio of contribution of $M$ to contribute of $E$ in the project? $1:1$ $1:2$ $1:4$ $2:1$ Quantitative Aptitude gate2016-ec-2 quantitative-aptitude work-time + – Milicevic3306 1.0k views answer comment Share Follow Add Sync Questions Print See all 2 Comments 2 2 Comments reply Tuhin Dutta commented May 7, 2019 i moved by Arjun May 18 reply Follow flag Ans is given B). 0 0 replyShare srestha commented May 8, 2019 i moved by Arjun May 18 reply Follow flag yes , B) will be ans 0 0 replyShare Please log in or register to add a comment.
0 0 votes Contribution = efficiency × hours/day × daysM’s work = 2 × 6 × (D/2) = 6DE’s work = 1 × 12 × D = 12DRatio (M : E) = 6D : 12D = 1 : 2 kp6602 answered Feb 21 kp6602 comment Share Follow 0 reply Please log in or register to add a comment.
