0 0 votes The transfer function $\dfrac{V_{2}(s)}{V_{1}(s)}$ of the circuit shown below is$\frac{0.5s+1}{s+1} \\ $$\frac{3s+6}{s+2} \\ $$\frac{s+2}{s+1} \\ $$\frac{s+1}{s+2}$ Circuit Analysis gate2013-ec signals-and-systems circuit-analysis + – Milicevic3306 370 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
