0 0 votes A system is described by the differential equation $\dfrac{\mathrm{d}^{2} y}{\mathrm{d} x} + 5\dfrac{\mathrm{d}y }{\mathrm{d} x} + 6y(t) = x(t).$ Let $x(t)$ be a rectangular pulse given by $x(t) = \begin{cases} 1&0<t<2 \\ 0&\text{otherwise} \end{cases}$ Assuming that $y(0) = 0$ and $\dfrac{\mathrm{d}y }{\mathrm{d} x} = 0$ at $t=0,$ the Laplace transform of $y(t)$ is $\frac{e^{-2s}}{s(s+2)(s+3)} \\$ $\frac{1-e^{-2s}}{s(s+2)(s+3)} \\$ $\frac{e^{-2s}}{(s+2)(s+3)} \\$ $\frac{1-e^{-2s}}{s(s+2)(s+3)} $ Differential Equations gate2013-ec differential-equations laplace-transform + – Milicevic3306 447 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
