1 1 vote A series $\text{RLC}$ circuit has a quality factor $\text{Q}$ of $1000$ at a center frequency of $10^{6} \; \mathrm{rad} / \mathrm{s}$. The possible values of $\text{R, L}$ and $\text{C}$ are $R=1 \; \Omega, L=1 \; \mu H$ and $C=1 \; \mu F$ $R=0.1 \; \Omega, L=1 \; \mu H$ and $C=1 \; \mu F$ $R=0.01 \; \Omega, L=1 \; \mu H$ and $C=1 \; \mu F$ $R=0.001 \; \Omega, L=1 \; \mu H$ and $C=1 \; \mu F$ Circuit Analysis gateece-2023 circuit-analysis rlc-circuits numerical-answers + – admin 799 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes W = 1/SQRT(LC)= 10 **6 Q = W*L/R 1000 = W*1/R = 10**6 * 10**-6/1000 = 1/1000 = .001 D IS CORRECT rashmi8303 answered Feb 11 rashmi8303 comment Share Follow 0 reply Please log in or register to add a comment.