1 votes 1 votes The transfer function of a plant is $T(s)=\dfrac{5}{(s+5)\left(s^{2}+s+1\right)}$. The second-order approximation of $T(s)$ using dominant pole concept is $\frac{1}{(s+5)(s+1)}$ $\frac{5}{(s+5)(s+1)}$ $\frac{5}{s^{2}+s+1}$ $\frac{1}{s^{2}+s+1}$ Others gate2007-ec + – admin asked Sep 19, 2022 edited Feb 24, 2023 by Lakshman Bhaiya admin 46.4k points 29 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.