2 2 votes A causal and stable $\text{LTI}$ system with impulse response $h(t)$ produces an output $y(t)$ for an input signal $x(t)$. A signal $x(0.5 t)$ is applied to another causal and stable $\text{LTI}$ system with impulse response $h(0.5 t)$. The resulting output is $\_\_\_\_\_\_\_$. $2 y(0.5 t)$ $4 y(0.5 t)$ $0.25 y(2 t)$ $0.25 y(0.25 t)$ Continuous-time Signals gateece-2024 linear-time-invariant-systems continuous-time-signals impulse-response signals-and-systems + – admin 1.9k views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes x(t)*h(t) = y(t) x(at)*h(at)=1/|a| *y(at) = 2y(0.5t) rashmi8303 answered Feb 9 rashmi8303 comment Share Follow 0 reply Please log in or register to add a comment.
