3 3 votes Consider a part of an electrical network as shown below. Some node voltages, and the current flowing through the $3 \Omega$ resistor are as indicated. The voltage (in Volts) at node $X$ is $\_\_\_\_\_\_$ $20 / 3$ $32 / 3$ $22 / 3$ $2 / 3$ Circuit Analysis gateec-2025 circuit-analysis numerical-answers network-solution-methods + – Shubham Sharma 2 2.2k views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
4 4 votes as V=I R : 9 - V = 1 *3 9-3 = V =6volt now (8-6)/3 = 2/3 is the current through the left branchX= 8 - 2*(2/3)X= 8 - (4/3)X=20/3 SAY123 answered Nov 25, 2025 SAY123 comment Share Follow 0 reply Please log in or register to add a comment.
3 3 votes 1=9-v(x)/4 V(X)=5 Answer=20/3 Monika_Monika answered Aug 17, 2025 Monika_Monika comment Share Follow 0 reply Please log in or register to add a comment.
1 1 vote Answer: C. 22/3 Niranjan 1 answered Sep 29, 2025 Niranjan 1 comment Share Follow 0 reply Please log in or register to add a comment.
