2 2 votes The address of the first location of a $256$ kilo byte $(\mathrm{KB})$ memory is $(2500)_{\mathrm{H}}$.Choose the correct address of the last location of the memory.$(2 \mathrm{FFF})_{\mathrm{H}}$$(124 \mathrm{FF})_{\mathrm{H}}$$(424 \mathrm{FF})_{\mathrm{H}}$$(324 \mathrm{FF})_{\mathrm{H}}$ Computer Organization gateec-2026 computer-organization numerical-answers + – gatecse 358 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes 256 KB is 2^18 bytes and 40000H so 2500 + 40000 -1 = 424FF Abhiral_Gupta answered Aug 8 Abhiral_Gupta comment Share Follow 0 reply Please log in or register to add a comment.