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2841
GATE ECE 2007 | Question: 81
Consider a linear system whose state space representation is $\dot{\mathbf{x}}(t)=\mathbf{A} \mathbf{x}(t)$. If the initial state vector of the system is $\mathbf{x}(0)=\left[\begin{array}{r}1 \\ -2\end{array}\right]$ ... $\left[\begin{array}{rr}0 & 1 \\ -2 & -3\end{array}\right]$
Consider a linear system whose state space representation is $\dot{\mathbf{x}}(t)=\mathbf{A} \mathbf{x}(t)$. If the initial state vector of the system is $\mathbf{x}(0)=\...
1 votes
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2843
GATE ECE 2008 | Question: 78
In the following network, the switch is closed at $t=0$ - and the sampling starts from $t=0$. The sampling frequency is $10 \mathrm{~Hz}$. The samples $x(n) \quad(n=0,1,2, \cdots \cdots)$ are given by $5\left(1-e^{-0.05 n}\right)$ $5 e^{-0.05 n}$ $5\left(1-e^{-5 n}\right)$ $5 e^{-5 n}$
In the following network, the switch is closed at $t=0$ - and the sampling starts from $t=0$. The sampling frequency is $10 \mathrm{~Hz}$.The samples $x(n) \quad(n=0,1,2,...
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2845
GATE ECE 1993 | Question 6.21
Sketch the waveform (with properly markedaxes) at the output of a matched filter matched for a signal $S(t)$, of duration $T$, given by $ S(t)= \begin{cases}\text { A } & \text { for } 0<t<\frac{2}{3} \mathrm{~T} \\ 6.22 & \text { for } \frac{2}{3} \mathrm{~T} \leq t<\mathrm{T}\end{cases} $
Sketch the waveform (with properly markedaxes) at the output of a matched filter matched for a signal $S(t)$, of duration $T$, given by $$ S(t)= \begin{cases}\text { A } ...
1 votes
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2847
GATE ECE 2010 | Question: 13
In the circuit shown, the device connected to $\text{Y5}$ can have address in the range $2000 – \mathrm{20FF}$ $\mathrm{2D00} – \mathrm{2DEF}$ $\mathrm{2E00} – \mathrm{2EFF}$ $\text{FD00 - FDFF}$
In the circuit shown, the device connected to $\text{Y5}$ can have address in the range$2000 – \mathrm{20FF}$$\mathrm{2D00} – \mathrm{2DEF}$$\mathrm{2E00} – \mathr...
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2848
GATE ECE 1991 | Question 3
The open loop transfer function of a feedback control system incorporating a dead time element is given by $ G(s)=\frac{K e^{-T s}}{s(s+1)} $ Where $\mathrm{K}>0$, and $\mathrm{T}>0$ are variable scalar parameters. (a) For a ... $\omega_0$ is the smallest value of $\omega$ satisfying the equation $\omega=\cot \omega T$
The open loop transfer function of a feedback control system incorporating a dead time element is given by$$ G(s)=\frac{K e^{-T s}}{s(s+1)} $$Where $\mathrm{K}>0$, and $\...
1 votes
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2849
GATE ECE 2011 | Question: 43
An input $\mathrm{x(t)}=\exp (-2 \mathrm{t)u(t})+\delta(\mathrm{t}-6)$ is applied to an LTI system with impulse response $\mathrm{h(t)=u(t})$. The output is $[1-\exp (-2 \mathrm{t)] u(t)+u(t}+6)$ $[1-\exp (-2 \mathrm{t)] u(t)+u(t}-6)$ $0.5[1-\exp (-2 \mathrm{t)] u(t)+u(t}+6)$ $0.5[1-\exp (-2 \mathrm{t)] u(t)+u(t}-6)$
An input $\mathrm{x(t)}=\exp (-2 \mathrm{t)u(t})+\delta(\mathrm{t}-6)$ is applied to an LTI system with impulse response $\mathrm{h(t)=u(t})$. The output is$[1-\exp (-2 \...
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2854
GATE ECE 1999 | Question 2.17
The $z$-transform of a signal is given by \[C(z)=\frac{1 z^{-1}\left(1-z^{-4}\right)}{4\left(1-z^{-1}\right)^{2}}\] Its final value is $1 / 4$ zero $1.0$ infinity
The $z$-transform of a signal is given by\[C(z)=\frac{1 z^{-1}\left(1-z^{-4}\right)}{4\left(1-z^{-1}\right)^{2}}\]Its final value is$1 / 4$zero$1.0$infinity
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2855
GATE ECE 1999 | Question 16
Consider a feedback system with the open-loop transfer function, given by \[ \mathrm{G}(s) \mathrm{H}(s)=\frac{\mathrm{K}}{s(2 s+1)} \] Examine the stability of the closed-loop system using Nyquist stability theory.
Consider a feedback system with the open-loop transfer function, given by\[\mathrm{G}(s) \mathrm{H}(s)=\frac{\mathrm{K}}{s(2 s+1)}\]Examine the stability of the closed-lo...
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2856
GATE ECE 2002 | Question: 8
Consider the circuit of the figure is. The $\text{op amp}$ used is ideal. In which mode is the $\text{BJT}$ operating (i.e. active, saturation or cut off)? Justify your answer. Obtain an expression relating the output current $\mathrm{I}_0$ ... $\beta=99$ and $\mathrm{V}_{\mathrm{BE}}=0.7 \mathrm{~V}$ )
Consider the circuit of the figure is. The $\text{op amp}$ used is ideal.In which mode is the $\text{BJT}$ operating (i.e. active, saturation or cut off)? Justify your an...
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2857
GATE ECE 1998 | Question 2.22
Quadrature multiplexing is the same as $\text{FDM}$ the same as $\text{TDM}$ a combination of $\text{FDM}$ and $\text{TDM}$ quite different from $\text{FDM}$ and $\text{TDM}$
Quadrature multiplexing isthe same as $\text{FDM}$the same as $\text{TDM}$a combination of $\text{FDM}$ and $\text{TDM}$quite different from $\text{FDM}$ and $\text{TDM}$...
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2858
GATE ECE 1998 | Question 2.25
For a given data rate, the bandwidth $\mathrm{B}_{p}$ of a $\text{BPSK}$ signal and the bandwidth $\text{B}_{0}$ of the $\mathrm{OOK}$ signal are related as $\mathrm{B}_{p}=\frac{\mathrm{B}_{0}}{4}$ $\text{B}_{p}=\frac{\text{B}_{0}}{2}$ $\mathrm{B}_{p}=\mathrm{B}_{0}$ $\text{B}_{p}=\text{2B}_{0}$
For a given data rate, the bandwidth $\mathrm{B}_{p}$ of a $\text{BPSK}$ signal and the bandwidth $\text{B}_{0}$ of the $\mathrm{OOK}$ signal are related as$\mathrm{B}_{p...
0 votes
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2859
GATE ECE 1998 | Question 2.35
The vector $\mathrm{H}$ in the far field of an antenna satisfies $\nabla \cdot \overrightarrow{\mathrm{H}}=0$ and $\nabla \times \overrightarrow{\mathrm{H}}=0$ $\nabla \cdot \overrightarrow{\mathrm{H}} \neq 0$ ... $\nabla \cdot \overrightarrow{\mathrm{H}} \neq 0$ and $\nabla \times \overrightarrow{\mathrm{H}}=0$
The vector $\mathrm{H}$ in the far field of an antenna satisfies$\nabla \cdot \overrightarrow{\mathrm{H}}=0$ and $\nabla \times \overrightarrow{\mathrm{H}}=0$$\nabla \cdo...
0 votes
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2860
GATE ECE 1998 | Question 3
Determine the frequency of resonance and the resonant impedance of the parallel circuit shown in the figure is. What happens when $\text{L}=\mathrm{CR}^{2}$ ?
Determine the frequency of resonance and the resonant impedance of the parallel circuit shown in the figure is. What happens when $\text{L}=\mathrm{CR}^{2}$ ?
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2863
GATE ECE 2003 | Question: 58
The circuit shown in the figure converts BCD to binary code Binary to excess $-3$ code Excess $-3$ to Gray code Gray to Binary code
The circuit shown in the figure convertsBCD to binary codeBinary to excess $-3$ codeExcess $-3$ to Gray codeGray to Binary code
0 votes
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2864
GATE ECE 2003 | Question: 82
If $\text{S}$ represents the carrier synchronization at the receiver and $\rho$ represents the bandwidth efficiency, then the correct statement for the coherent binary $\text{PSK}$ is $\rho=0.5, S$ is required $\rho=1.0, S$ is required $\rho=0.5, \mathrm{~S}$ is not required $\rho=1.0, S$ is not required
If $\text{S}$ represents the carrier synchronization at the receiver and $\rho$ represents the bandwidth efficiency, then the correct statement for the coherent binary $\...
0 votes
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2865
GATE ECE 2004 | Question: 45
Assuming that the $\beta$ of the transistor is extremely large and $\text{V}_{\text{B E}}=0.7 \mathrm{~V}, \text{I}_{\text{C}}$ and $\text{V}_{\text{CE}}$ ... $\mathrm{I}_{\mathrm{C}}=0.5 \mathrm{~mA}, \mathrm{~V}_{\mathrm{CE}}=3.9 \mathrm{~V}$
Assuming that the $\beta$ of the transistor is extremely large and $\text{V}_{\text{B E}}=0.7 \mathrm{~V}, \text{I}_{\text{C}}$ and $\text{V}_{\text{CE}}$ in the circuit ...
0 votes
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2866
GATE ECE 2004 | Question: 55
The number of memory cycles required to execute the following $8085$ instructions $\text{LDA 3000 H}$ $\text{LXI D, FOF 1 H}$ would be $2$ for (I) and $2$ for (II) $4$ for (I) and $3$ for (II) $3$ for (I) and $3$ for (II) $3$ for (I) and $4$ for (II)
The number of memory cycles required to execute the following $8085$ instructions$\text{LDA 3000 H}$$\text{LXI D, FOF 1 H}$would be$2$ for (I) and $2$ for (II)$4$ for (I)...
0 votes
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2869
GATE ECE 1995 | Question 3.3
In a $\text{JFET}$ if (A) the pinch-off voltage decreases (B) the transconductance increases (C) the transit time of the carriers in the channel is reduced the channel doping is reduced the channel length is increased the conductivity of the channel increased the channel length is reduced the Gate area is reduced
In a $\text{JFET}$ if(A) the pinch-off voltage decreases(B) the transconductance increases(C) the transit time of the carriers in the channel is reducedthe channel dopin...
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2870
GATE ECE 1995 | Question 3.5
For a $\text{TTL}$ gate, match the following (A) $\mathrm{V}_{\mathrm{OH}}$ $\text{(min)}$ (B) $\mathrm{V}_{\mathrm{IH}}$ $\text{(min)}$ (C) $\mathrm{V}_{\mathrm{OL}}$ $\text{(max)}$. $2.4$ volts $1.5$ volts $0.4$ volts $2.0$ volts $0.8$ volts
For a $\text{TTL}$ gate, match the following(A) $\mathrm{V}_{\mathrm{OH}}$ $\text{(min)}$(B) $\mathrm{V}_{\mathrm{IH}}$ $\text{(min)}$(C) $\mathrm{V}_{\mathrm{OL}}$ $\tex...
0 votes
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2872
GATE ECE 1994 | Question 4.7
(a) Single side band (1) Envelope detector (b) Amplitude (2) Integrate and dump modulation (c) Binary phase-shift (3) Hilbert transform keying (4) Ratio detector (5) Phase-locked loop
(a) Single side band(1) Envelope detector(b) Amplitude(2) Integrate and dump modulation(c) Binary phase-shift(3) Hilbert transform keying (4) Ratio detector (5) Phase-loc...
1 votes
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2873
GATE ECE 2007 | Question: 41
The Boolean expression $Y=\overline{A} \;\overline{B}\; \overline{C} D+\overline{A} B C \overline{D}+A \overline{B}\; \overline{C} D+A B \overline{C}\; \overline{D}$ ... $Y=\overline{A} B C \overline{D}+\overline{B}\; \overline{C} D+A B \overline{C} \;\overline{D}$
The Boolean expression $Y=\overline{A} \;\overline{B}\; \overline{C} D+\overline{A} B C \overline{D}+A \overline{B}\; \overline{C} D+A B \overline{C}\; \overline{D}$ can ...
1 votes
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2875
GATE ECE 2007 | Question: 61
During transmission over a certain binary communication channel, bit errors occur independently with probability $p$. The probability of AT MOST one bit in error in a block of $n$ bits is given by $p^{n}$ $1-p^{n}$ $n p(1-p)^{n-1}+(1-p)^{n}$ $1-(1-p)^{n}$
During transmission over a certain binary communication channel, bit errors occur independently with probability $p$. The probability of AT MOST one bit in error in a blo...
1 votes
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2879
GATE ECE 2010 | Question: 60
$25$ persons are in a room. $15$ of them play hockey, $17$ of them play football and $10$ of them play both hockey and football. Then the number of persons playing neither hockey nor football is: $2$ $17$ $13$ $3$
$25$ persons are in a room. $15$ of them play hockey, $17$ of them play football and $10$ of them play both hockey and football. Then the number of persons playing neithe...
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