0 0 votes The voltage across an impedance in a network is $V(s)=z(s) I(s)$, where $V(s)$, $Z(s)$ are the Laplace transforms of the corresponding time function $v(t), z(t)$ and $i(t)$. The voltage $v(t)$ is: $v(t)=z(t) \cdot v(t)$ $v(t)=\int_0^1 i(t) \cdot z(t-\tau) d \tau$ $v(t)=\int_0^1 i(t) \cdot z(t+\tau) d \tau$ $v(t)=z(t)+i(t)$ Control Systems gate1991-ec circuit-analysis laplace-transform continuous-time-signals + – admin 515 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
