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Consider the following circuit using an ideal OPAMP. The I-V characteristics of the diode is described by the relation $I=I_{0}\left(e^{\frac{V}{V_{T}}}-1\right)$ where $V_{T}=25 \; \mathrm{mV}, I_{0}=1 \; \mu \mathrm{A}$ and $\mathrm{V}$ is the voltage across the diode (taken as positive for forward bias).

For an input voltage $V_{i}=-1 \mathrm{~V}$, the output voltage $V_{o}$ is

- $0 \mathrm{~V}$
- $0.1 \mathrm{~V}$
- $0.7 \mathrm{~V}$
- $1.1 \mathrm{~V}$