2 views

In the circuit shown, $V_{C}$ is $0$ volts at $t=0 \; \mathrm{sec}$. For $t>0$, the capacitor current $i_{c}(t)$, where $t$ is in seconds, is given by

1. $0.50 \exp (-25 t) \; \mathrm{mA}$
2. $0.25 \exp (-25 t) \; \mathrm{mA}$
3. $0.50 \exp (-12.5 t) \; \mathrm{mA}$
4. $0.25 \exp (-6.25 t) \; \mathrm{mA}$