0 0 votes The circuit shown in the figure has initial current $i_{t}\left(0^{-}\right)=1 \mathrm{~A}$ through the inductor and an initial voltage $v_{c}\left(0^{-}\right)=-1 \mathrm{~V}$ across the capacitor. For input $v(t)=u(t)$, the Laplace transform of the current $i(t)$ for $t \geq 0$ is $\frac{\mathrm{s}}{s^{2}+s+1}$ $\frac{s+2}{s^{2}+s+1}$ $\frac{s-2}{s^{2}+s+1}$ $\frac{s-2}{s^{2}+s+1}$ Circuit Analysis gate2004-ec circuit-analysis laplace-transform + – admin 309 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
