0 0 votes A voltage $1000 \sin\omega t\:\: \text{Volts}$ is applied across $YZ.$ Assuming ideal diodes, the voltage measured across $WX$ in $\text{Volts},$ is $\sin \omega t$ $(\sin \omega t \:+ \mid \sin \omega t \mid)/2$ $(\sin \omega t \: - \mid \sin \omega t \mid)/2$ $0$ for all $t$ Analog Circuits gate2013-ec analog-circuits diode-circuits + – Milicevic3306 443 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
