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The switch has been in position $1$ for a long time and abruptly changes to position $2$ at $t = 0$.

If time $t$ is in seconds, the capacitor voltage $V_{C}$ (in volts) for $t > 0$ is given by

- $4\left ( 1- \text{ exp }\left ( -t/0.5 \right ) \right )$
- $10- 6 \text{ exp }\left ( -t/0.5 \right )$
- $4\left ( 1-\text{ exp }\left ( -t/0.6 \right ) \right )$
- $10 -6 \text{ exp }\left ( -t/0.6 \right )$