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Recent questions tagged gate2003-ec

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41
GATE ECE 2003 | Question: 40
Match items in Group $1$ with items in Group $2,$ ... $\text{P - 3 Q - 4 R - 1 S - 2}$ $\text{P - 2 Q - 1 R - 4 S - 3}$
Match items in Group $1$ with items in Group $2,$ most suitably.$$\begin{array}{ll} \textbf{Group 1} & \textbf{Group 2} \\ \text{P LED} & \text{1 Heavy doping} \\ \text{Q...
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42
GATE ECE 2003 | Question: 42
A particular green $\text{LED}$ emits light of wavelength $5490 \text{ A}$. The energy bandgap of the semiconductor material used there is (Planck's constant = $6.626 \times 10^{-34} \mathrm{~J-s})$ $2.26 \; \mathrm{eV}$ $1.98 \; \mathrm{eV}$ $1.17 \; \mathrm{eV}$ $0.74 \; \mathrm{eV}$
A particular green $\text{LED}$ emits light of wavelength $5490 \text{ A}$. The energy bandgap of the semiconductor material used there is (Planck's constant = $6.626 \ti...
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44
GATE ECE 2003 | Question: 44
If $\mathrm{P}$ is Passivation, $\mathrm{Q}$ is $n$-well implant, $\mathrm{R}$ is metallization and $S$ is source/drain diffusion, then the order in which they are carried out in a standard $n$-well CMOS fabrication process, is P-Q-R-S Q-S-R-P R-P-S-Q S-R-Q-P
If $\mathrm{P}$ is Passivation, $\mathrm{Q}$ is $n$-well implant, $\mathrm{R}$ is metallization and $S$ is source/drain diffusion, then the order in which they are carrie...
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45
GATE ECE 2003 | Question: 45
An amplifier without feedback has a voltage gain of $50$, input resistance of $1 \mathrm{~K} \Omega$ and output resistance of $2.5 \mathrm{~K} \Omega$ ... $1 / 5 \mathrm{~K} \Omega$ $5 \mathrm{~K} \Omega$ $11 \mathrm{~K} \Omega$
An amplifier without feedback has a voltage gain of $50$, input resistance of $1 \mathrm{~K} \Omega$ and output resistance of $2.5 \mathrm{~K} \Omega$. The input resistan...
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47
GATE ECE 2003 | Question: 47
The oscillator circuit shown in the figure is has an ideal inverting amplifier. Its frequency of oscillation (in $\mathrm{Hz}$ ) is $\frac{1}{(2 \pi \sqrt{6} \mathrm{RC})}$ $\frac{1}{(2 \pi \mathrm{RC})}$ $\frac{1}{(\sqrt{6} \mathrm{RC})}$ $\frac{1}{\sqrt{6}(2 \pi \mathrm{RC})}$
The oscillator circuit shown in the figure is has an ideal inverting amplifier. Its frequency of oscillation (in $\mathrm{Hz}$ ) is$\frac{1}{(2 \pi \sqrt{6} \mathrm{RC})}...
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48
GATE ECE 2003 | Question: 48
The output voltage of the regulated power supply shown in the figure is $3 \mathrm{~V}$ $6 \mathrm{~V}$ $9 \mathrm{~V}$ $12 \mathrm{~V}$
The output voltage of the regulated power supply shown in the figure is$3 \mathrm{~V}$$6 \mathrm{~V}$$9 \mathrm{~V}$$12 \mathrm{~V}$
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49
GATE ECE 2003 | Question: 49
The action of a $\text{JFET}$ in its equivalent circuit can best be represented as a Current Controlled Current Source Current Controlled Voltage Source Voltage Controlled Voltage Source Voltage Controlled Current Source
The action of a $\text{JFET}$ in its equivalent circuit can best be represented as aCurrent Controlled Current SourceCurrent Controlled Voltage SourceVoltage Controlled V...
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50
GATE ECE 2003 | Question: 50
If the $\text{op-amp}$ in the figure is idea, the output voltage Voult will be equal to $1 \mathrm{~V}$ $6 \mathrm{~V}$ $14 \mathrm{~V}$ $17 \mathrm{~V}$
If the $\text{op-amp}$ in the figure is idea, the output voltage Voult will be equal to$1 \mathrm{~V}$$6 \mathrm{~V}$$14 \mathrm{~V}$$17 \mathrm{~V}$
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51
GATE ECE 2003 | Question: 51
Three identical amplifiers with each one having a voltage gain of $50,$ input resistance of $1 \mathrm{~K} \Omega$ and output resistance of $250 \; \Omega$, are cascaded. The open circuit voltage gain of the combined amplifier is $49 \mathrm{~dB}$ $51 \mathrm{~dB}$ $98 \mathrm{~dB}$ $102 \mathrm{~dB}$
Three identical amplifiers with each one having a voltage gain of $50,$ input resistance of $1 \mathrm{~K} \Omega$ and output resistance of $250 \; \Omega$, are cascaded....
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55
GATE ECE 2003 | Question: 55
A $4$ bit ripple counter and a $4$ bit synchronous counter are made using flip flops having a propagation delay of $10 \mathrm{~ns}$ each. If the worst case delay in the ripple counter and the synchronous counter be $R$ and $S$ ... $\mathrm{R}=30 \mathrm{~ns}, \mathrm{~S}=10 \mathrm{~ns}$
A $4$ bit ripple counter and a $4$ bit synchronous counter are made using flip flops having a propagation delay of $10 \mathrm{~ns}$ each. If the worst case delay in the ...
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56
GATE ECE 2003 | Question: 56
The DTL, TTL, ECL and CMOS families of digital $\mathrm{IC}_{\mathrm{s}}$ are compared in the following $4$ ... $\text{P}$ $\text{Q}$ $\text{R}$ $\text{S}$
The DTL, TTL, ECL and CMOS families of digital $\mathrm{IC}_{\mathrm{s}}$ are compared in the following $4$ columns$$\begin{array}{lllll} & \textbf{(P)} & \textbf{(Q)} & ...
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58
GATE ECE 2003 | Question: 58
The circuit shown in the figure converts BCD to binary code Binary to excess $-3$ code Excess $-3$ to Gray code Gray to Binary code
The circuit shown in the figure convertsBCD to binary codeBinary to excess $-3$ codeExcess $-3$ to Gray codeGray to Binary code
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61
GATE ECE 2003 | Question: 61
Let $X$ and $Y$ be two statistically independent random variables uniformly distributed in the ranges $(-1,1)$ and $(-2,1)$ respectively. Let $Z=X+Y$. Then the probability that $(Z \leq-2)$ is zero $\frac{1}{6}$ $\frac{1}{3}$ $\frac{1}{12}$
Let $X$ and $Y$ be two statistically independent random variables uniformly distributed in the ranges $(-1,1)$ and $(-2,1)$ respectively. Let $Z=X+Y$. Then the probabilit...
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66
GATE ECE 2003 | Question: 66
Let $Y$ and $Z$ be the random variables obtained by sampling $X(t)$ at $t=2$ and $t=4$ respectively. Let $W$ $=Y-Z$. The variance of $W$ is $13.36$ $9.36$ $2.64$ $8.00$
Let $Y$ and $Z$ be the random variables obtained by sampling $X(t)$ at $t=2$ and $t=4$ respectively. Let $W$ $=Y-Z$. The variance of $W$ is$13.36$$9.36$$2.64$$8.00$
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68
GATE ECE 2003 | Question: 68
The signal flow graph of a system is shown in the figure. The transfer function $\frac{C(s)}{R(s)}$ of the system is $\frac{6}{s^{2}+29 s+6}$ $\frac{6 s}{s^{2}+29 s+6}$ $\frac{s(s+2)}{s^{2}+29 s+6}$ $\frac{s(s+27)}{s^{2}+29 s+6}$
The signal flow graph of a system is shown in the figure. The transfer function $\frac{C(s)}{R(s)}$ of the system is$\frac{6}{s^{2}+29 s+6}$$\frac{6 s}{s^{2}+29 s+6}$$\fr...
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69
GATE ECE 2003 | Question: 69
The root locus of the system $\mathrm{G}(\mathrm{s}) \mathrm{H}(s)$ $=\frac{\mathrm{K}}{s(s+2)(s+3)}$ has the break-away point located at $(-0.5,0)$ $(-2.548,0)$ $(-4,0)$ $(-0.784,0)$
The root locus of the system $\mathrm{G}(\mathrm{s}) \mathrm{H}(s)$ $=\frac{\mathrm{K}}{s(s+2)(s+3)}$ has the break-away point located at$(-0.5,0)$$(-2.548,0)$$(-4,0)$$(-...
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70
GATE ECE 2003 | Question: 70
The approximate Bode magnitude plot of a minimum-phase system is shown in the figure. The transfer function of the system is $10^8 \frac{(s+0.1)^3}{(s+10)^2(s+100)}$ $10^{7} \frac{(s+0.1)^3}{(s+10)(s+100)}$ $10^8 \frac{(s+0.1)^2}{(s+10)^2(s+100)}$ $10^9 \frac{(s+0.1)^3}{(s+10)(s+100)^2}$
The approximate Bode magnitude plot of a minimum-phase system is shown in the figure. The transfer function of the system is$10^8 \frac{(s+0.1)^3}{(s+10)^2(s+100)}$$10^{7...
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71
GATE ECE 2003 | Question: 71
A second-order system has the transfer function $\frac{C(s)}{R(s)}=\frac{4}{s^{2}+4 s+4}$. With $r(t)$ as the unit-step function, the response $c(t)$ of the system is represented by Fig. $(a)$ Fig. $(b)$ Fig. $(c)$ Fig. $(d)$
A second-order system has the transfer function$\frac{C(s)}{R(s)}=\frac{4}{s^{2}+4 s+4}$.With $r(t)$ as the unit-step function, the response $c(t)$ of the system is repre...
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72
GATE ECE 2003 | Question: 72
The gain margin and the phase margin of a feedback system with $\mathrm{G}(\mathrm{s}) \mathrm{H}(\mathrm{s})=\frac{\mathrm{s}}{(\mathrm{s}+100)^{3}}$ are $0 \mathrm{~dB}, 0^{\circ}$ $\infty, \infty$ $\infty, 0^{\circ}$ $88.5 \mathrm{~dB}, \infty$
The gain margin and the phase margin of a feedback system with $\mathrm{G}(\mathrm{s}) \mathrm{H}(\mathrm{s})=\frac{\mathrm{s}}{(\mathrm{s}+100)^{3}}$ are$0 \mathrm{~dB},...
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73
GATE ECE 2003 | Question: 73
The zero-input response of a system given by the state-space equation $\left[\begin{array}{l}\dot{x}_{1} \\ \dot{x}_{2}\end{array}\right]=\left[\begin{array}{ll}1 & 0 \\ 1 & 1\end{array}\right]\left[\begin{array}{l}x_{1} \\ x_{2}\end{array}\right]$ ... $\left[\begin{array}{c}t \\ t e^{t}\end{array}\right]$
The zero-input response of a system given by the state-space equation$\left[\begin{array}{l}\dot{x}_{1} \\ \dot{x}_{2}\end{array}\right]=\left[\begin{array}{ll}1 & 0 \\ 1...
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75
GATE ECE 2003 | Question: 75
The data for Q. 75-76 are given below. Solve the problems and choose the correct answers. Let $m(t)=\cos \left[\left(4 \pi \times 10^{3}\right) t\right]$ be the message signal and $\left.c(t)=5 \cos \left[2 \pi \times 10^{b}\right) t\right]$ ... $\frac{1}{2}$ $\frac{1}{4}$ $\frac{1}{3}$ $\frac{1}{8}$
The data for Q. 75-76 are given below. Solve the problems and choose the correct answers.Let $m(t)=\cos \left[\left(4 \pi \times 10^{3}\right) t\right]$ be the message si...
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77
GATE ECE 2003 | Question: 77
Choose the correct one from among the alternative $\text{A, B, C. D}$ after matching an item in Group $1$ with the most appropriate item in Group $2.$ ... $\text{P - 6 Q - 1 R - 3 S - 2}$ $\text{P - 5 Q - 6 R - 1 S - 3}$
Choose the correct one from among the alternative $\text{A, B, C. D}$ after matching an item in Group $1$ with the most appropriate item in Group $2.$$\begin{array}{ll}\q...
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79
GATE ECE 2003 | Question: 79
A sinusoidal signal with peak-to-peak amplitude of $1.536 \mathrm{~V}$ is quantized into $128$ levels using a mid-rise uniform quantizer. The quantization-noise power is $0.768 \mathrm{~V}$ $48 \times 10^{-6} \mathrm{~V}^{2}$ $12 \times 10^{-6} \mathrm{~V}^{2}$ $3.072 \mathrm{~V}$
A sinusoidal signal with peak-to-peak amplitude of $1.536 \mathrm{~V}$ is quantized into $128$ levels using a mid-rise uniform quantizer. The quantization-noise power is$...
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