GO Electronics
Login
Register
Dark Mode
Brightness
Profile
Edit Profile
Messages
My favorites
My Updates
Logout
Filter
Profile
Wall
Recent activity
All questions
All answers
Exams Taken
All Blogs
Questions by Milicevic3306
0
votes
0
answers
761
GATE ECE 2012 | Question: 20
A system with transfer function $G(s)=\frac{(s^2+9)(s+2)}{(s+1)(s+3)(s+4)}$ is excited by $\sin(\omega t)$. The steady-state output of the system is zero at $\omega=1\:rad/s$ $\omega=2\:rad/s$ $\omega=3\:rad/s$ $\omega=4\:rad/s$
A system with transfer function$$G(s)=\frac{(s^2+9)(s+2)}{(s+1)(s+3)(s+4)}$$is excited by $\sin(\omega t)$. The steady-state output of the system is zero at$\omega=1\:rad...
138
views
asked
Mar 25, 2018
Network Solution Methods
gate2012-ec
network-solution-methods
transfer-function
+
–
1
votes
0
answers
762
GATE ECE 2012 | Question: 19
In the sum of products function $f(X,Y,Z)=\sum(2,3,4,5)$, the prime implicants are $\overline{X}Y,X\overline{Y}$ $\overline{X}Y,X\overline{Y}\;\overline{Z},X\overline{Y}Z$ $\overline{X}Y\overline{Z},\overline{X}YZ,X\overline{Y}$ $\overline{X}Y\overline{Z},\overline{X}YZ,X\overline{Y}\;\overline{Z},X\overline{Y}Z$
In the sum of products function $f(X,Y,Z)=\sum(2,3,4,5)$, the prime implicants are$\overline{X}Y,X\overline{Y}$$\overline{X}Y,X\overline{Y}\;\overline{Z},X\overline{Y}Z$$...
156
views
asked
Mar 25, 2018
Number Representations
gate2012-ec
digital-circuits
boolean-algebra
+
–
0
votes
0
answers
763
GATE ECE 2012 | Question: 18
If $x[n]=(\frac{1}{3})^{|n|}-(\frac{1}{2})^{|n|}u[n]$, then the region of convergence (ROC) of its Z-transform in the Z-plane will be $\frac{1}{3}\lt |z|\lt 3$ $\frac{1}{3}\lt |z|\lt \frac{1}{2}$ $\frac{1}{2}\lt |z|\lt 3$ $\frac{1}{3}\lt |z|$
If $x[n]=(\frac{1}{3})^{|n|}-(\frac{1}{2})^{|n|}u[n]$, then the region of convergence (ROC) of its Z-transform in the Z-plane will be$\frac{1}{3}\lt |z|\lt 3$$\frac{1}{3}...
105
views
asked
Mar 25, 2018
Numerical Methods
gate2012-ec
numerical-methods
convergence-criteria
+
–
0
votes
0
answers
764
GATE ECE 2012 | Question: 17
The radiation pattern of an antenna in spherical co-ordinates is given by $F(\theta)=\cos^4\theta\:\:\:;\:\:\:0\le \theta\le \frac{\pi}{2}$ The directivity of the antenna is $10\:dB$ $12.6\:dB$ $11.5\:dB$ $18\:dB$
The radiation pattern of an antenna in spherical co-ordinates is given by$$F(\theta)=\cos^4\theta\:\:\:;\:\:\:0\le \theta\le \frac{\pi}{2}$$The directivity of the antenna...
75
views
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
antennas
+
–
0
votes
0
answers
765
GATE ECE 2012 | Question: 16
A coaxial cable with an inner diameter of $1\:mm$ and outer diameter of $2.4\:mm$ is filled with a dielectric of relative permittivity $10.89$. Given $\mu_0=4\pi\times10^{-7}\:H/m$, $\varepsilon_0=\frac{10^{-9}}{36\pi}\:F/m$, the characteristic impedance of the cable is $330\:\Omega$ $100\:\Omega$ $143.3\:\Omega$ $43.4\:\Omega$
A coaxial cable with an inner diameter of $1\:mm$ and outer diameter of $2.4\:mm$ is filled with a dielectric of relative permittivity $10.89$. Given $\mu_0=4\pi\times10^...
97
views
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
impedance
+
–
0
votes
0
answers
766
GATE ECE 2012 | Question: 15
A source alphabet consists of $N$ symbols with the probability of the first two symbols being the same. A source encoder increases the probability of the first symbol by a small amount $\varepsilon$ and decreases that of the second by $\varepsilon$. After encoding, the entropy of the source increases remains the same increases only if $N=2$ decreases
A source alphabet consists of $N$ symbols with the probability of the first two symbols being the same. A source encoder increases the probability of the first symbol by ...
173
views
asked
Mar 25, 2018
Probability and Statistics
gate2012-ec
probability-and-statistics
probability
+
–
0
votes
0
answers
767
GATE ECE 2012 | Question: 14
In the circuit shown $Y=\overline{A} \overline{B}+\bar{C}$ $Y=(A+B)C$ $Y=(\overline{A}+\overline{B})\overline{C}$ $Y=AB+C$
In the circuit shown$Y=\overline{A} \overline{B}+\bar{C}$$Y=(A+B)C$$Y=(\overline{A}+\overline{B})\overline{C}$$Y=AB+C$
83
views
asked
Mar 25, 2018
Others
gate2012-ec
to-be-tagged
+
–
0
votes
0
answers
768
GATE ECE 2012 | Question: 13
The diodes and capacitors in the circuit shown are ideal. The voltage $v(t)$ across the diode $D1$ is $\cos(\omega t)-1$ $\sin(\omega t)$ $1-\cos(\omega t)$ $1-\sin(\omega t)$
The diodes and capacitors in the circuit shown are ideal. The voltage $v(t)$ across the diode $D1$ is$\cos(\omega t)-1$$\sin(\omega t)$$1-\cos(\omega t)$$1-\sin(\omega t)...
94
views
asked
Mar 25, 2018
Analog Circuits
gate2012-ec
analog-circuits
+
–
0
votes
0
answers
769
GATE ECE 2012 | Question: 12
With initial condition $x(1)=0.5$, the solution of the differential equation, $t\frac{dx}{dt}+x=t$ is $x=t-\frac{1}{2}$ $x=t^2-\frac{1}{2}$ $x=\frac{t^2}{2}$ $x=\frac{t}{2}$
With initial condition $x(1)=0.5$, the solution of the differential equation,$$t\frac{dx}{dt}+x=t$$ is$x=t-\frac{1}{2}$$x=t^2-\frac{1}{2}$$x=\frac{t^2}{2}$$x=\frac{t}{2}$...
86
views
asked
Mar 25, 2018
Differential Equations
gate2012-ec
differential-equations
+
–
0
votes
0
answers
770
GATE ECE 2012 | Question: 11
The unilateral Laplace transform of $f(t)$ is $\frac{1}{s^2+s+1}$. The unilateral Laplace transform of $tf(t)$ is $-\frac{s}{(s^2+s+1)^2}$ $-\frac{2s+1}{(s^2+s+1)^2}$ $\frac{s}{(s^2+s+1)^2}$ $\frac{2s+1}{(s^2+s+1)^2}$
The unilateral Laplace transform of $f(t)$ is $\frac{1}{s^2+s+1}$. The unilateral Laplace transform of $tf(t)$ is$-\frac{s}{(s^2+s+1)^2}$$-\frac{2s+1}{(s^2+s+1)^2}$$\frac...
141
views
asked
Mar 25, 2018
Network Solution Methods
gate2012-ec
network-solution-methods
laplace-transform
+
–
0
votes
0
answers
771
GATE ECE 2012 | Question: 10
The average power delivered to an impedance $(4-j3)\:\Omega$ by a current $5\cos(100\pi t+100)\:A$ is $44.2\:W$ $50\:W$ $62.5\:W$ $125\:W$
The average power delivered to an impedance $(4-j3)\:\Omega$ by a current $5\cos(100\pi t+100)\:A$ is$44.2\:W$$50\:W$$62.5\:W$$125\:W$
70
views
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
impedance
+
–
0
votes
0
answers
772
GATE ECE 2012 | Question: 9
In the following figure, $C_1$ and $C_2$ are ideal capacitors. $C_1$ has been charged to $12\:V$ before the ideal switch $S$ is closed at $t=0$. The current $i(t)$ for all $t$ is zero a step function an exponentially decaying function an impulse function
In the following figure, $C_1$ and $C_2$ are ideal capacitors. $C_1$ has been charged to $12\:V$ before the ideal switch $S$ is closed at $t=0$. The current $i(t)$ for al...
108
views
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
+
–
0
votes
0
answers
773
GATE ECE 2012 | Question: 8
The $i-v$ characteristics of the diode in the circuit given below are $i = \begin{cases} \frac{v-0.07}{500}\:A, & v\ge0.7\:V \\ \:\:\:\:\:\:\:\:0\:A, & v \lt 0.7\:V \end{cases}$ The current in the circuit is $10\:mA$ $9.3\:mA$ $6.67\:mA$ $6.2\:mA$
The $i-v$ characteristics of the diode in the circuit given below are$$i = \begin{cases} \frac{v-0.07}{500}\:A, & v\ge0.7\:V \\ \:\:\:\:\:\:\:\:0\:A, & v \lt 0.7\:V \en...
119
views
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
carrier-transport
+
–
0
votes
0
answers
774
GATE ECE 2012 | Question: 7
The output $Y$ of a $2-\text{bit}$ comparator is logic $1$ whenever the $2-\text{bit}$ input $A$ is greater than the $2-\text{bit}$ input $B$. The number of combinations for which the output is logic $1$, is $4$ $6$ $8$ $10$
The output $Y$ of a $2-\text{bit}$ comparator is logic $1$ whenever the $2-\text{bit}$ input $A$ is greater than the $2-\text{bit}$ input $B$. The number of combinations ...
81
views
asked
Mar 25, 2018
Digital Circuits
gate2012-ec
digital-circuits
+
–
0
votes
0
answers
775
GATE ECE 2012 | Question: 6
Consider the given circuit. In the circuit, the race around does not occur occurs when $\text{CLK}=0$ occurs when $\text{CLK}=1$ and $A=B=1$ occurs when $\text{CLK}=1$ and $A=B=0$
Consider the given circuit.In the circuit, the race arounddoes not occuroccurs when $\text{CLK}=0$occurs when $\text{CLK}=1$ and $A=B=1$occurs when $\text{CLK}=1$ and $A=...
151
views
asked
Mar 25, 2018
Number Representations
gate2012-ec
digital-circuits
sequential-circuit
flip-flop
+
–
0
votes
0
answers
776
GATE ECE 2012 | Question: 5
The electric field of a uniform plane electromagnetic wave in free space, along the positive $x$ direction, is given by $\overrightarrow{E}=10(\hat{a}_y+j\hat{a}_z)e^{-j\:25x}$. The frequency and polarization of the wave, respectively, are $1.2\:GHz$ and left circular $4\:Hz$ and left circular $1.2\:GHz$ and right circular $4\:Hz$ and right circular
The electric field of a uniform plane electromagnetic wave in free space, along the positive $x$ direction, is given by $\overrightarrow{E}=10(\hat{a}_y+j\hat{a}_z)e^{-j\...
157
views
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
+
–
0
votes
0
answers
777
GATE ECE 2012 | Question: 4
A plane wave propagating in air with $\overrightarrow{E}=(8\hat{a}_x+6\hat{a}_y+5\hat{a}_z)e^{j(\omega t+3x-4y)}\:V/m$ is incident on a perfectly conducting slab positioned at $x\le0$ . The $\overrightarrow{E}$ ... $(-8\hat{a}_x+6\hat{a}_y-5\hat{a}_z)e^{j(\omega t-3x-4y)}\:V/m$
A plane wave propagating in air with $\overrightarrow{E}=(8\hat{a}_x+6\hat{a}_y+5\hat{a}_z)e^{j(\omega t+3x-4y)}\:V/m$ is incident on a perfectly conducting slab position...
129
views
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
propagation
+
–
0
votes
0
answers
778
GATE ECE 2012 | Question: 3
In a baseband communications link, frequencies upto $3500\:Hz$ are used for signaling. Using a raised cosine pulse with $75\%$ excess bandwidth and for no inter-symbol interference, the maximum possible signaling rate in the symbols per second is $1750$ $2625$ $4000$ $5250$
In a baseband communications link, frequencies upto $3500\:Hz$ are used for signaling. Using a raised cosine pulse with $75\%$ excess bandwidth and for no inter-symbol in...
90
views
asked
Mar 25, 2018
Communications
gate2012-ec
communications
calculation-of-bandwidth
+
–
0
votes
0
answers
779
GATE ECE 2012 | Question: 2
The power spectral density of a real process $X(t)$ for positive frequencies is shown below. The values of $E[X^2(t)]$ and $ \mid E[X(t)] \mid$, respectively, are $\frac{6000}{\pi}\:,\:0$ $\frac{6400}{\pi}\:,\:0$ $\frac{6400}{\pi}\:,\:\frac{20}{(\pi\sqrt2)}$ $\frac{6000}{\pi}\:,\:\frac{20}{(\pi\sqrt2)}$
The power spectral density of a real process $X(t)$ for positive frequencies is shown below. The values of $E[X^2(t)]$ and $ \mid E[X(t)] \mid$, respectively, are$\frac{6...
110
views
asked
Mar 25, 2018
Communications
gate2012-ec
communications
autocorrelation-and-power-spectral-density
+
–
0
votes
0
answers
780
GATE ECE 2012 | Question: 1
The current $i_b$ through the base of a silicon $npn$ transistor is $1+0.1\cos(10000\pi t)\:mA$. At $300\:K$, the $r_\pi$ in the small signal model of the transistor is $250\:\Omega$ $27.5\:\Omega$ $25\:\Omega$ $22.5\:\Omega$
The current $i_b$ through the base of a silicon $npn$ transistor is $1+0.1\cos(10000\pi t)\:mA$. At $300\:K$, the $r_\pi$ in the small signal model of the transistor is$2...
106
views
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
intrinsic-and-extrinsic-silicon
+
–
Page:
« prev
1
...
17
18
19
20
GO Electronics
Email or Username
Show
Hide
Password
I forgot my password
Remember
Log in
Register