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Questions by Milicevic3306
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votes
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answers
721
GATE ECE 2012 | Question: 60
One of the parts $(A, B, C, D)$ in the sentence given below contains an ERROR. Which one of the following is INCORRECT? I requested that he should be given the driving test today instead of tomorrow. requested that should be given the driving test instead of tomorrow
One of the parts $(A, B, C, D)$ in the sentence given below contains an ERROR. Which one of the following is INCORRECT?I requested that he should be given the driving tes...
101
views
asked
Mar 25, 2018
Verbal Aptitude
gate2012-ec
verbal-aptitude
english-grammar
+
–
0
votes
0
answers
722
GATE ECE 2012 | Question: 59
Which one of the following options is the closest in meaning to the word given below? Latitude Eligibility Freedom Coercion Meticulousness
Which one of the following options is the closest in meaning to the word given below?LatitudeEligibilityFreedomCoercionMeticulousness
107
views
asked
Mar 25, 2018
Verbal Aptitude
gate2012-ec
verbal-aptitude
most-appropriate-word
+
–
0
votes
0
answers
723
GATE ECE 2012 | Question: 58
Choose the most appropriate word from the options given below to complete the following sentence: Given the seriousness of the situation that he had to face, his ___ was impressive. beggary nomenclature jealousy nonchalance
Choose the most appropriate word from the options given below to complete the followingsentence:Given the seriousness of the situation that he had to face, his ___ was im...
105
views
asked
Mar 25, 2018
Verbal Aptitude
gate2012-ec
verbal-aptitude
most-appropriate-word
+
–
0
votes
0
answers
724
GATE ECE 2012 | Question: 57
Choose the most appropriate alternative from the options given below to complete the following sentence: If the tired soldier wanted to lie down, he _______ the mattress out on the balcony. should take shall take should have taken will have taken
Choose the most appropriate alternative from the options given below to complete the followingsentence:If the tired soldier wanted to lie down, he _______ the mattress ou...
107
views
asked
Mar 25, 2018
Verbal Aptitude
gate2012-ec
verbal-aptitude
english-grammar
+
–
0
votes
0
answers
725
GATE ECE 2012 | Question: 56
If $(1.001)^{1259}=3.52$ and $(1.001)^{2062}=7.85,$ then $(1.001)^{3321}=?$ $2.23$ $4.33$ $11.37$ $27.64$
If $(1.001)^{1259}=3.52$ and $(1.001)^{2062}=7.85,$ then $(1.001)^{3321}=?$$2.23$$4.33$$11.37$$27.64$
117
views
asked
Mar 25, 2018
Quantitative Aptitude
gate2012-ec
numerical-ability
number-system
+
–
0
votes
0
answers
726
GATE ECE 2012 | Question: 55
The transfer function of a compensator is given as $G_c(s)=\frac{s+a}{s+b}$ The phase of the above lead compensator is maximum at $\sqrt{2}$ rad/s $\sqrt{3}$ rad/s $\sqrt{6}$ rad/s $\frac{1}{\sqrt{3}}$ rad/s
The transfer function of a compensator is given as$$G_c(s)=\frac{s+a}{s+b}$$The phase of the above lead compensator is maximum at$\sqrt{2}$ rad/s$\sqrt{3}$ rad/s$\sqrt{6}...
114
views
asked
Mar 25, 2018
Network Solution Methods
gate2012-ec
network-solution-methods
diodes
transfer-function
+
–
0
votes
0
answers
727
GATE ECE 2012 | Question: 54
The transfer function of a compensator is given as $G_c(s)=\frac{s+a}{s+b}$ $G_c(s)$ is a lead compensator if $a=1,b=2$ $a=3,b=2$ $a=-3,b=-1$ $a=3,b=1$
The transfer function of a compensator is given as$$G_c(s)=\frac{s+a}{s+b}$$$G_c(s)$ is a lead compensator if$a=1,b=2$$a=3,b=2$$a=-3,b=-1$$a=3,b=1$
207
views
asked
Mar 25, 2018
Network Solution Methods
gate2012-ec
network-solution-methods
transfer-function
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–
0
votes
0
answers
728
GATE ECE 2012 | Question: 53
An infinitely long uniform solid wire of radius $a$ carries a uniform dc current of density $\overrightarrow{j}$. A hole of radius $b$ (b < a) ia now drilled along the length of the wire at a distance $d$ from the center of the wire as shown ... uniform and depends only on $d$ uniform and depends only on $b$ uniform and depends only on both $b$ and $d$ non uniform
An infinitely long uniform solid wire of radius $a$ carries a uniform dc current of density $\overrightarrow{j}$.A hole of radius $b$ (b < a) ia now drilled along the len...
234
views
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
carrier-transport
+
–
0
votes
0
answers
729
GATE ECE 2012 | Question: 52
An infinitely long uniform solid wire of radius $a$ carries a uniform dc current of density $\overrightarrow{j}$. The magnetic field at a distance $r$ from the center of the wire is proportional to $r$ for $r\lt a$ and $\frac{1}{r^2}$ for $r\gt a$ $0$ for $r\lt a$ ... $r\lt a$ and $\frac{1}{r}$ for $r\gt a$ $0$ for $r\lt a$ and $\frac{1}{r^2}$ for $r\gt a$
An infinitely long uniform solid wire of radius $a$ carries a uniform dc current of density $\overrightarrow{j}$.The magnetic field at a distance $r$ from the center of t...
119
views
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
carrier-transport
electronic-devices
+
–
0
votes
0
answers
730
GATE ECE 2012 | Question: 51
In the three dimensional view of a silicon n-channel MOS transistor shown below, $\delta=20\:nm$. The transistor is of width $1\: \mu m$. The depletion width formed at every p-n junction is $10\:nm$. The relative permittivities of $Si$ and $SiO_2$, respectively, are ... $2\:fF$ $7\:fF$ $2\:pF$ $7\:pF$
In the three dimensional view of a silicon n-channel MOS transistor shown below, $\delta=20\:nm$. The transistor is of width $1\: \mu m$. The depletion width formed at ev...
83
views
asked
Mar 25, 2018
Analog Circuits
gate2012-ec
analog-circuits
mos-transistor
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–
0
votes
0
answers
731
GATE ECE 2012 | Question: 50
In the three dimensional view of a silicon n-channel MOS transistor shown below, $\delta=20\:nm$. The transistor is of width $1\: \mu m$. The depletion width formed at every p-n junction is $10\:nm$. The relative permittivities of $Si$ and $SiO_2$, respectively, are ... $0.7\:fF$ $0.7\:pF$ $0.35\:fF$ $0.24\:pF$
In the three dimensional view of a silicon n-channel MOS transistor shown below, $\delta=20\:nm$. The transistor is of width $1\: \mu m$. The depletion width formed at ev...
153
views
asked
Mar 25, 2018
Analog Circuits
gate2012-ec
analog-circuits
mos-transistor
+
–
0
votes
0
answers
732
GATE ECE 2012 | Question: 49
With $10\:V$ dc connected at port A in the linear nonreciprocal two-port network shown below, the following were observed: $1\: \Omega$ connected at port B draws a current of $3\:A$ $2.5\: \Omega$ connected at port B draws a current of $2\:A$ For the same network, with ... $6\:V$ $7\:V$ $8\:V$ $9\:V$
With $10\:V$ dc connected at port A in the linear nonreciprocal two-port network shown below, the following were observed:$1\: \Omega$ connected at port B draws a current...
152
views
asked
Mar 25, 2018
Network Solution Methods
gate2012-ec
two-port-network
network-solution-methods
+
–
0
votes
0
answers
733
GATE ECE 2012 | Question: 48
With $10\:V$ dc connected at port A in the linear nonreciprocal two-port network shown below, the following were observed: $1\: \Omega$ connected at port B draws a current of $3\:A$ $2.5\: \Omega$ connected at port B draws a current of $2\:A$ With $10\: V$ dc connected at ... $\frac{3}{7}\: A$ $\frac{5}{7}\: A$ $1\: A$ $\frac{9}{7}\: A$
With $10\:V$ dc connected at port A in the linear nonreciprocal two-port network shown below, the following were observed:$1\: \Omega$ connected at port B draws a current...
124
views
asked
Mar 25, 2018
Network Solution Methods
gate2012-ec
two-port-network
network-solution-methods
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–
0
votes
0
answers
734
GATE ECE 2012 | Question: 47
Given that $A=\begin{bmatrix} -5 &-3 \\ 2 &0\end{bmatrix}$ and $I=\begin{bmatrix} 1 & 0 \\ 0 &1\end{bmatrix}$, the value of $A^3$ is $15\:A+12\:I$ $19\:A+30\:I$ $17\:A+15\:I$ $17\:A+21\:I$
Given that$A=\begin{bmatrix} -5 &-3 \\ 2 &0\end{bmatrix}$ and $I=\begin{bmatrix} 1 & 0 \\ 0 &1\end{bmatrix}$, the value of $A^3$ is$15\:A+12\:I$$19\:A+30\:I$$17\:A+15\:I$...
110
views
asked
Mar 25, 2018
Linear Algebra
gate2012-ec
linear-algebra
matrices
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–
0
votes
0
answers
735
GATE ECE 2012 | Question: 46
The maximum value of $f(x)=x^3-9x^2+24x+5$ in the interval $[1,6]$ is $21$ $25$ $41$ $46$
The maximum value of $f(x)=x^3-9x^2+24x+5$ in the interval $[1,6]$ is$21$$25$$41$$46$
88
views
asked
Mar 25, 2018
Calculus
gate2012-ec
calculus
maxima-minima
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–
0
votes
0
answers
736
GATE ECE 2012 | Question: 45
If $V_A-V_B=6\:V$, then $V_C-V_D$ is $-5\:V$ $2\:V$ $3\:V$ $6\:V$
If $V_A-V_B=6\:V$, then $V_C-V_D$ is$-5\:V$$2\:V$$3\:V$$6\:V$
88
views
asked
Mar 25, 2018
Others
gate2012-ec
to-be-tagged
+
–
0
votes
0
answers
737
GATE ECE 2012 | Question: 44
The voltage gain $A_v$ of the circuit shown below is $\mid A_v \mid\approx 200$ $\mid A_v\mid \approx 100$ $ \mid A_v \mid \approx 20$ $\mid A_v \mid \approx 10$
The voltage gain $A_v$ of the circuit shown below is$\mid A_v \mid\approx 200$$\mid A_v\mid \approx 100$$ \mid A_v \mid \approx 20$$\mid A_v \mid \approx 10$
94
views
asked
Mar 25, 2018
Analog Circuits
gate2012-ec
analog-circuits
+
–
0
votes
0
answers
738
GATE ECE 2012 | Question: 43
The state transition diagram for the logic circuit shown is
The state transition diagram for the logic circuit shown is
130
views
asked
Mar 25, 2018
Number Representations
gate2012-ec
digital-circuits
+
–
0
votes
0
answers
739
GATE ECE 2012 | Question: 42
Let $y[n]$ denote the convolution of $h[n]$ and $g[n]$, where $h[n]=(\frac{1}{2})^nu[n]$ and $g[n]$ is a casual sequence. If $y[0]=1$ and $y[1]=\frac{1}{2}$, then $g[1]$ equals $0$ $\frac{1}{2}$ $1$ $\frac{3}{2}$
Let $y[n]$ denote the convolution of $h[n]$ and $g[n]$, where $h[n]=(\frac{1}{2})^nu[n]$ and $g[n]$ is a casual sequence. If $y[0]=1$ and $y =\frac{1}{2}$, then $g $ equa...
98
views
asked
Mar 25, 2018
Continuous-time Signals
gate2012-ec
continuous-time-signals
signals-and-systems
convolution
+
–
0
votes
0
answers
740
GATE ECE 2012 | Question: 41
The circuit shown is a low pass filter with $f_{3\:dB}=\frac{1}{(R_1+R_2)C}\: rad/s$ high pass filter with $f_{3\:dB}=\frac{1}{R_1C}\: rad/s$ low pass filter with $f_{3\:dB}=\frac{1}{R_1C}\: rad/s$ high pass filter with $f_{3\:dB}=\frac{1}{(R_1+R_2)C}\: rad/s$
The circuit shown is a low pass filter with $f_{3\:dB}=\frac{1}{(R_1+R_2)C}\: rad/s$high pass filter with $f_{3\:dB}=\frac{1}{R_1C}\: rad/s$low pass filter with $f_{3\:dB...
139
views
asked
Mar 25, 2018
Continuous-time Signals
gate2012-ec
continuous-time-signals
digital-filter-design-techniques
+
–
0
votes
0
answers
741
GATE ECE 2012 | Question: 40
The magnetic field along the propagation direction inside a rectangular waveguide with the cross-section shown in the figure is $H_Z=3\:\cos(2.094\times10^2x)\:\cos(2.618\times10^2y)\:\cos(6.283\times10^{10}t-\beta z)$ The phase velocity $v_p$ of the wave inside the waveguide satisfies $v_p\gt c$ $v_p=c$ $0\lt v_p\lt c$ $v_p=0$
The magnetic field along the propagation direction inside a rectangular waveguide with the cross-section shown in the figure is$$H_Z=3\:\cos(2.094\times10^2x)\:\cos(2.618...
230
views
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
propagation
+
–
0
votes
0
answers
742
GATE ECE 2012 | Question: 39
The signal $m(t)$ as shown is applied both to a phase modulator (with $k_p$ as the phase constant) and a frequency modulator (with $k_f$ as the frequency constant) having the same carrier frequency. The ratio $\frac{k_p}{k_f}$ (in $rad/Hz$) for the same maximum phase deviation is $8\pi$ $4\pi$ $2\pi$ $\pi$
The signal $m(t)$ as shown is applied both to a phase modulator (with $k_p$ as the phase constant) and a frequency modulator (with $k_f$ as the frequency constant) having...
151
views
asked
Mar 25, 2018
Communications
gate2012-ec
communications
frequency-modulation
+
–
0
votes
0
answers
743
GATE ECE 2012 | Question: 38
A binary symmetric channel (BSC) has a transition probability of $\frac{1}{8}$. If the binary transmit symbol $X$ is such that $P(X=0)\:=\:\frac{9}{10}$, then the probability of error for an optimum receiver will be $\frac{7}{80}$ $\frac{63}{80}$ $\frac{9}{10}$ $\frac{1}{10}$
A binary symmetric channel (BSC) has a transition probability of $\frac{1}{8}$. If the binary transmit symbol $X$ is such that $P(X=0)\:=\:\frac{9}{10}$, then the probabi...
240
views
asked
Mar 25, 2018
Probability and Statistics
gate2012-ec
probability-and-statistics
probability
+
–
0
votes
0
answers
744
GATE ECE 2012 | Question: 37
In the CMOS circuit shown, electron and hole mobilities are equal, and $M1$ and $M2$ are equally sized. The device $M1$ is in the linear region if $V_{in}\lt 1.875\:V$ $1.875\:V\lt V_{in}\lt 3.125\:V$ $V_{in}\gt 3.125\:V$ $0\lt V_{in}\lt 5\:V$
In the CMOS circuit shown, electron and hole mobilities are equal, and $M1$ and $M2$ are equally sized. The device $M1$ is in the linear region if$V_{in}\lt 1.875\:V$$1.8...
85
views
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
cmos
+
–
0
votes
1
answer
745
GATE ECE 2012 | Question: 36
A fair coin is tossed till head appears for the first time. The probability that the number of required tosses is odd, is $\frac{1}{3}$ $\frac{1}{2}$ $\frac{2}{3}$ $\frac{3}{4}$
A fair coin is tossed till head appears for the first time. The probability that the number of required tosses is odd, is$\frac{1}{3}$$\frac{1}{2}$$\frac{2}{3}$$\frac{3}{...
182
views
asked
Mar 25, 2018
Probability and Statistics
gate2012-ec
probability-and-statistics
probability
+
–
0
votes
0
answers
746
GATE ECE 2012 | Question: 35
The direction of vector $A$ is radially outward from the origin, with $|A|=kr^n$ where $r^2=x^2+y^2+z^2$ and $k$ is a constant. The value of $n$ for which $\triangledown.A=0$ is $-2$ $2$ $1$ $0$
The direction of vector $A$ is radially outward from the origin, with $|A|=kr^n$ where $r^2=x^2+y^2+z^2$ and $k$ is a constant. The value of $n$ for which $\triangledown....
209
views
asked
Mar 25, 2018
Vector Analysis
gate2012-ec
vector-analysis
+
–
0
votes
0
answers
747
GATE ECE 2012 | Question: 34
Consider the differential equation $\frac{d^2y(t)}{dt^2}+2\frac{dy(t)}{dt}+y(t)=\delta(t)$ with $y(t)\big|_{t=0^-}=-2$ and $\frac{dy}{dt}\big|_{t=0^-}=0$. The numerical value of $\frac{dy}{dt}\big|_{t=0^+}$ is $-2$ $-1$ $0$ $1$
Consider the differential equation$\frac{d^2y(t)}{dt^2}+2\frac{dy(t)}{dt}+y(t)=\delta(t)$ with $y(t)\big|_{t=0^-}=-2$ and $\frac{dy}{dt}\big|_{t=0^-}=0$.The numerical val...
115
views
asked
Mar 25, 2018
Differential Equations
gate2012-ec
differential-equations
+
–
0
votes
0
answers
748
GATE ECE 2012 | Question: 33
Assuming both the voltage sources are in phase, the value of $R$ for which maximum power is transferred from circuit $A$ to circuit $B$ is $0.8\:\Omega$ $1.4\:\Omega$ $2\:\Omega$ $2.8\:\Omega$
Assuming both the voltage sources are in phase, the value of $R$ for which maximum power is transferred from circuit $A$ to circuit $B$ is$0.8\:\Omega$$1.4\:\Omega$$2\:\O...
76
views
asked
Mar 25, 2018
Analog Circuits
gate2012-ec
analog-circuits
+
–
0
votes
0
answers
749
GATE ECE 2012 | Question: 32
The state variable description of an LTI system is given by ... $a_1\neq 0,a_2=0,a_3\neq 0$ $a_1=0,a_2\neq0,a_3\neq 0$ $a_1=0,a_2\neq0,a_3=0$ $a_1\neq 0,a_2\neq0,a_3=0$
The state variable description of an LTI system is given by$$\begin{pmatrix} \dot{x_1}\\ \dot{x_2}\\ \dot{x_3} \end{pmatrix}=\begin{pmatrix} 0 & a_1 & 0\\ 0 & 0 & a_2\\a_...
515
views
asked
Mar 25, 2018
Continuous-time Signals
gate2012-ec
continuous-time-signals
signals-and-systems
linear-time-invariant-systems
+
–
0
votes
0
answers
750
GATE ECE 2012 | Question: 31
The Fourier transform of a signal $h(t)$ is $H(j\omega)=(2\cos\omega)(\sin2\omega)/\omega$. The value of $h(0)$ is $\frac{1}{4}$ $\frac{1}{2}$ $1$ $2$
The Fourier transform of a signal $h(t)$ is $H(j\omega)=(2\cos\omega)(\sin2\omega)/\omega$. The value of $h(0)$ is$\frac{1}{4}$$\frac{1}{2}$$1$$2$
303
views
asked
Mar 25, 2018
Continuous-time Signals
gate2012-ec
continuous-time-signals
signals-and-systems
fourier-transform
+
–
0
votes
0
answers
751
GATE ECE 2012 | Question: 30
The feedback system shown below oscillates at $2\:rad/s$ when $K=2$ and $a=0.75$ $K=3$ and $a=0.75$ $K=4$ and $a=0.5$ $K=2$ and $a=0.5$
The feedback system shown below oscillates at $2\:rad/s$ when$K=2$ and $a=0.75$$K=3$ and $a=0.75$$K=4$ and $a=0.5$$K=2$ and $a=0.5$
96
views
asked
Mar 25, 2018
Analog Circuits
gate2012-ec
analog-circuits
oscillator
+
–
0
votes
0
answers
752
GATE ECE 2012 | Question: 29
The input $x(t)$ and output $y(t)$ of a system are related as $y(t)=\underset{-\infty}{\int}x(\tau)\cos(3\tau)d\tau$. The system is time-invariant and stable stable and not time-invariant time-invariant and not stable not time-invariant and not stable
The input $x(t)$ and output $y(t)$ of a system are related as $y(t)=\underset{-\infty}{\int}x(\tau)\cos(3\tau)d\tau$. The system istime-invariant and stablestable and not...
82
views
asked
Mar 25, 2018
Analog Circuits
gate2012-ec
analog-circuits
+
–
0
votes
0
answers
753
GATE ECE 2012 | Question: 28
A trasmission line with a characteristic impedance of $100\:\Omega$ is used to match a $50\:\Omega$ section to a $200\:\Omega$ section. If the matching is to be done both at $429\:MHz$ and $1\:GHz$, the length of the transmission line can be approximately $82.5\:cm$ $1.05\:m$ $1.58\:m$ $1.75\:m$
A trasmission line with a characteristic impedance of $100\:\Omega$ is used to match a $50\:\Omega$ section to a $200\:\Omega$ section. If the matching is to be done both...
82
views
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
transmission-lines
+
–
0
votes
0
answers
754
GATE ECE 2012 | Question: 27
A BPSK scheme operating over an AWGN channel with noise power spectral density of $\frac{N_o}{2}$, uses equiprobable signals $s_1(t)=\sqrt{\frac{2E}{T}}\sin(\omega_ct)$ and $s_2(t)=-\sqrt{\frac{2E}{T}}\sin(\omega_ct)$ over the symbol interval $(0,T)$. If the local oscillator ... $Q(\sqrt{\frac{E}{N_o}})$ $Q(\sqrt{\frac{E}{2N_o}})$ $Q(\sqrt{\frac{E}{4N_o}})$
A BPSK scheme operating over an AWGN channel with noise power spectral density of $\frac{N_o}{2}$, uses equiprobable signals $s_1(t)=\sqrt{\frac{2E}{T}}\sin(\omega_ct)$ a...
99
views
asked
Mar 25, 2018
Communications
gate2012-ec
communications
autocorrelation-and-power-spectral-density
+
–
0
votes
0
answers
755
GATE ECE 2012 | Question: 26
The source of a silicon ($n_i=10^{10}\:per\:cm^3$) n-channel MOS transistor has an area of $1\:sq\:\mu m$ and a depth of $1\:\mu m$. If the dopant density in the source is $10^{19}/cm^3$, the number of holes in the source region with the above volume is approximately $10^7$ $100$ $10$ $0$
The source of a silicon ($n_i=10^{10}\:per\:cm^3$) n-channel MOS transistor has an area of $1\:sq\:\mu m$ and a depth of $1\:\mu m$. If the dopant density in the source i...
86
views
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
silicon
+
–
0
votes
0
answers
756
GATE ECE 2012 | Question: 25
If $x=\sqrt{-1}$, then the value of $x^x$ is $e^{\frac{-\pi}{2}}$ $e^{\frac{\pi}{2}}$ $x$ $1$
If $x=\sqrt{-1}$, then the value of $x^x$ is$e^{\frac{-\pi}{2}}$$e^{\frac{\pi}{2}}$$x$$1$
87
views
asked
Mar 25, 2018
Calculus
gate2012-ec
calculus
+
–
0
votes
0
answers
757
GATE ECE 2012 | Question: 24
Two independent random variables $X$ and $Y$ are uniformly distributed in the interval $[-1,1]$. The probability that max$[X,Y]$ is less than $\frac{1}{2}$ is $\frac{3}{4}$ $\frac{9}{16}$ $\frac{1}{4}$ $\frac{2}{3}$
Two independent random variables $X$ and $Y$ are uniformly distributed in the interval $[-1,1]$. The probability that max$[X,Y]$ is less than $\frac{1}{2}$ is$\frac{3}{4}...
103
views
asked
Mar 25, 2018
Probability and Statistics
gate2012-ec
probability-and-statistics
probability
independent-events
random-variable
+
–
0
votes
0
answers
758
GATE ECE 2012 | Question: 23
Given $f(z)=\frac{1}{z+1}-\frac{2}{z+3}$. If $C$ is a counterclockwise path in the z-plane such that $\mid z+1 \mid=1$, the value of $\frac{1}{2\pi j}\oint_cf(z)dz$ is $-2$ $-1$ $1$ $2$
Given $f(z)=\frac{1}{z+1}-\frac{2}{z+3}$. If $C$ is a counterclockwise path in the z-plane such that $\mid z+1 \mid=1$, the value of $\frac{1}{2\pi j}\oint_cf(z)dz$ is$-2...
107
views
asked
Mar 25, 2018
Vector Analysis
gate2012-ec
vector-analysis
+
–
0
votes
0
answers
759
GATE ECE 2012 | Question: 22
In the circuit shown below, the current through the inductor is $\frac{2}{1+j}\:A$ $\frac{-1}{1+j}\:A$ $\frac{1}{1+j}\:A$ $0\:A$
In the circuit shown below, the current through the inductor is$\frac{2}{1+j}\:A$$\frac{-1}{1+j}\:A$$\frac{1}{1+j}\:A$$0\:A$
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Mar 25, 2018
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GATE ECE 2012 | Question: 21
The impedance looking into nodes $1$ and $2$ in the given circuit is $50\:\Omega$ $100\:\Omega$ $5\:k\Omega$ $10.1\:k\Omega$
The impedance looking into nodes $1$ and $2$ in the given circuit is$50\:\Omega$$100\:\Omega$$5\:k\Omega$$10.1\:k\Omega$
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Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
impedance
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