1 1 vote The base of an $\text{npn BJT T1}$ has a linear doping profile $N_{B}\left ( x \right )$ as shown below. The base of another $\text{npn BJT T2}$ has a uniform doping $N_{B}$ of $10^{17}cm^{-3}$. All other parameters are identical for both the devices. Assuming that the hole density profile is the same as that of doping, the common-emitter current gain of $\text{T2}$ is approximately $2.0$ times that of $\text{T1}$. approximately $0.3$ times that of $\text{T1}$. approximately $2.5$ times that of $\text{T1}$. approximately $0.7$ times that of $\text{T1}$. Analog Circuits gate2020-ec analog-circuits bipolar-junction-transistor + – go_editor 894 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
