1 1 vote A $4$-bit priority encoder has inputs $D_{3}, D_{2}, D_{1}$, and $D_{0}$ in descending order of priority. The two-bit output $A B$ is generated as $00,01,10$, and 11 corresponding to inputs $D_{3}, D_{2}, D_{1}$, and $D_{0}$, respectively. The Boolean expression of the output bit $B$ is $\_\_\_\_\_\_\_$. $\overline{D_{3}} \overline{D_{2}}$ $\overline{D_{3}} D_{2}+\overline{D_{3}} \overline{D_{1}}$ $D_{3} \overline{D_{2}}+\overline{D_{3}} D_{1}$ $\overline{D_{3}} \overline{D_{1}}$ Digital Circuits gateece-2024 digital-circuits boolean-algebra + – admin 3.2k views answer comment Share Follow Add Sync Questions Print See 1 comment 1 1 comment reply MuniKumar commented Jul 11, 2024 reply Follow flag D3 +(D2)'D1 0 0 replyShare Please log in or register to add a comment.
0 0 votes Ans: (B) hrupam answered Sep 13, 2025 hrupam comment Share Follow 0 reply Please log in or register to add a comment.