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Assuming that the Op-amp in the circuit shown is ideal, $V_{o}$ is given by

1. $\frac{5}{2}V_{1}-3V_{2} \\$
2. $2V_{1}-\frac{5}{2}V_{2} \\$
3. $-\frac{3}{2}V_{1}+\frac{7}{2}V_{2} \\$
4. $-3V_{1}+\frac{11}{2}V_{2}$