0 votes 0 votes The current $I$ in the circuit shown is ______________. $1.25 \times 10^{-3} \; \text{A}$ $0.75 \times 10^{-3} \; \text{A}$ $ – 0.5 \times 10^{-3} \; \text{A}$ $1.16 \times 10^{-3} \; \text{A}$ Others gateece-2022 + – Arjun asked Feb 15, 2022 • edited Sep 12, 2022 by gatecse Arjun 6.6k points 189 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.