0 0 votes The transistor in the circuit shown in the figure is so biased ($dc$ biasing network is not shown) that the $dc$ collecter current $I_{c}=1 \mathrm{~mA}$. Supply is $V_{cc}=5 \mathrm{~V}$. The network components have following values \[\begin{array}{l} R_{c}=2 k \Omega, \\ R_{s}=1.4 k \Omega \\ R_{E}=100 \Omega \end{array}\] and The transistor has specifications. $\beta=100$ and base spreading resistance \[r_{b b}=100 \; \Omega .\] Assume $\frac{k T}{q}=25 \; \mathrm{mV}$ Evaluate small signal Voltage Gain $\mathrm{A}_{\mathrm{V}_{\mathrm{s}}}$ at a frequency of $10 \; \mathrm{kHz}$, and Input Resistance $\mathrm{R}_{i}$ for two cases $\text{CE}$, the hypass capacitor across $R_{E}$ is $25 \mu \mathrm{F}$. The bypass capacitor $C_{E}$ is removed leaving $R_{E}$ unbypassed BJT and MOSFET Amplifiers gate1997-ec bipolar-junction-transistor amplifier numerical-answers circuit-analysis + – admin 414 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.