1 1 vote A simplified small-signal equivalent circuit of a BJT-based amplifier is given below. The small-signal voltage gain $V_{o} / V_{S}$ (in $\mathrm{V} / \mathrm{V})$ is $\_\_\_\_\_\_$ $\frac{-\beta \mathrm{R}_{\mathrm{L}}}{\mathrm{R}_{\mathrm{S}}+\mathrm{r}_{\pi}}$ $\frac{+\beta \mathrm{R}_{\mathrm{L}}}{\mathrm{R}_{\mathrm{S}}}$ $\frac{-\beta \mathrm{R}_{\mathrm{L}}}{\mathrm{R}_{\mathrm{S}}}$ $\frac{+\beta \mathrm{R}_{\mathrm{L}}}{\mathrm{R}_{\mathrm{S}}+\mathrm{r}_{\pi}}$ BJT and MOSFET Amplifiers gateec-2025 analog-circuits circuit-analysis bjt-and-mosfet-amplifiers small-signal-analysis + – Shubham Sharma 2 906 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes A followlocus7 answered Dec 12, 2025 followlocus7 comment Share Follow 0 reply Please log in or register to add a comment.
