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Recent questions tagged gate2012-ec
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41
GATE ECE 2012 | Question: 25
If $x=\sqrt{-1}$, then the value of $x^x$ is $e^{\frac{-\pi}{2}}$ $e^{\frac{\pi}{2}}$ $x$ $1$
If $x=\sqrt{-1}$, then the value of $x^x$ is$e^{\frac{-\pi}{2}}$$e^{\frac{\pi}{2}}$$x$$1$
Milicevic3306
16.0k
points
85
views
Milicevic3306
asked
Mar 25, 2018
Calculus
gate2012-ec
calculus
+
–
0
votes
0
answers
42
GATE ECE 2012 | Question: 23
Given $f(z)=\frac{1}{z+1}-\frac{2}{z+3}$. If $C$ is a counterclockwise path in the z-plane such that $\mid z+1 \mid=1$, the value of $\frac{1}{2\pi j}\oint_cf(z)dz$ is $-2$ $-1$ $1$ $2$
Given $f(z)=\frac{1}{z+1}-\frac{2}{z+3}$. If $C$ is a counterclockwise path in the z-plane such that $\mid z+1 \mid=1$, the value of $\frac{1}{2\pi j}\oint_cf(z)dz$ is$-2...
Milicevic3306
16.0k
points
104
views
Milicevic3306
asked
Mar 25, 2018
Vector Analysis
gate2012-ec
vector-analysis
+
–
0
votes
0
answers
43
GATE ECE 2012 | Question: 22
In the circuit shown below, the current through the inductor is $\frac{2}{1+j}\:A$ $\frac{-1}{1+j}\:A$ $\frac{1}{1+j}\:A$ $0\:A$
In the circuit shown below, the current through the inductor is$\frac{2}{1+j}\:A$$\frac{-1}{1+j}\:A$$\frac{1}{1+j}\:A$$0\:A$
Milicevic3306
16.0k
points
130
views
Milicevic3306
asked
Mar 25, 2018
Others
gate2012-ec
to-be-tagged
+
–
0
votes
0
answers
44
GATE ECE 2012 | Question: 20
A system with transfer function $G(s)=\frac{(s^2+9)(s+2)}{(s+1)(s+3)(s+4)}$ is excited by $\sin(\omega t)$. The steady-state output of the system is zero at $\omega=1\:rad/s$ $\omega=2\:rad/s$ $\omega=3\:rad/s$ $\omega=4\:rad/s$
A system with transfer function$$G(s)=\frac{(s^2+9)(s+2)}{(s+1)(s+3)(s+4)}$$is excited by $\sin(\omega t)$. The steady-state output of the system is zero at$\omega=1\:rad...
Milicevic3306
16.0k
points
131
views
Milicevic3306
asked
Mar 25, 2018
Network Solution Methods
gate2012-ec
network-solution-methods
transfer-function
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–
0
votes
0
answers
45
GATE ECE 2012 | Question: 21
The impedance looking into nodes $1$ and $2$ in the given circuit is $50\:\Omega$ $100\:\Omega$ $5\:k\Omega$ $10.1\:k\Omega$
The impedance looking into nodes $1$ and $2$ in the given circuit is$50\:\Omega$$100\:\Omega$$5\:k\Omega$$10.1\:k\Omega$
Milicevic3306
16.0k
points
88
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
impedance
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–
0
votes
0
answers
46
GATE ECE 2012 | Question: 26
The source of a silicon ($n_i=10^{10}\:per\:cm^3$) n-channel MOS transistor has an area of $1\:sq\:\mu m$ and a depth of $1\:\mu m$. If the dopant density in the source is $10^{19}/cm^3$, the number of holes in the source region with the above volume is approximately $10^7$ $100$ $10$ $0$
The source of a silicon ($n_i=10^{10}\:per\:cm^3$) n-channel MOS transistor has an area of $1\:sq\:\mu m$ and a depth of $1\:\mu m$. If the dopant density in the source i...
Milicevic3306
16.0k
points
85
views
Milicevic3306
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
silicon
+
–
1
votes
0
answers
47
GATE ECE 2012 | Question: 19
In the sum of products function $f(X,Y,Z)=\sum(2,3,4,5)$, the prime implicants are $\overline{X}Y,X\overline{Y}$ $\overline{X}Y,X\overline{Y}\;\overline{Z},X\overline{Y}Z$ $\overline{X}Y\overline{Z},\overline{X}YZ,X\overline{Y}$ $\overline{X}Y\overline{Z},\overline{X}YZ,X\overline{Y}\;\overline{Z},X\overline{Y}Z$
In the sum of products function $f(X,Y,Z)=\sum(2,3,4,5)$, the prime implicants are$\overline{X}Y,X\overline{Y}$$\overline{X}Y,X\overline{Y}\;\overline{Z},X\overline{Y}Z$$...
Milicevic3306
16.0k
points
155
views
Milicevic3306
asked
Mar 25, 2018
Number Representations
gate2012-ec
digital-circuits
boolean-algebra
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–
0
votes
0
answers
48
GATE ECE 2012 | Question: 15
A source alphabet consists of $N$ symbols with the probability of the first two symbols being the same. A source encoder increases the probability of the first symbol by a small amount $\varepsilon$ and decreases that of the second by $\varepsilon$. After encoding, the entropy of the source increases remains the same increases only if $N=2$ decreases
A source alphabet consists of $N$ symbols with the probability of the first two symbols being the same. A source encoder increases the probability of the first symbol by ...
Milicevic3306
16.0k
points
173
views
Milicevic3306
asked
Mar 25, 2018
Probability and Statistics
gate2012-ec
probability-and-statistics
probability
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–
0
votes
0
answers
49
GATE ECE 2012 | Question: 18
If $x[n]=(\frac{1}{3})^{|n|}-(\frac{1}{2})^{|n|}u[n]$, then the region of convergence (ROC) of its Z-transform in the Z-plane will be $\frac{1}{3}\lt |z|\lt 3$ $\frac{1}{3}\lt |z|\lt \frac{1}{2}$ $\frac{1}{2}\lt |z|\lt 3$ $\frac{1}{3}\lt |z|$
If $x[n]=(\frac{1}{3})^{|n|}-(\frac{1}{2})^{|n|}u[n]$, then the region of convergence (ROC) of its Z-transform in the Z-plane will be$\frac{1}{3}\lt |z|\lt 3$$\frac{1}{3}...
Milicevic3306
16.0k
points
105
views
Milicevic3306
asked
Mar 25, 2018
Numerical Methods
gate2012-ec
numerical-methods
convergence-criteria
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–
0
votes
0
answers
50
GATE ECE 2012 | Question: 12
With initial condition $x(1)=0.5$, the solution of the differential equation, $t\frac{dx}{dt}+x=t$ is $x=t-\frac{1}{2}$ $x=t^2-\frac{1}{2}$ $x=\frac{t^2}{2}$ $x=\frac{t}{2}$
With initial condition $x(1)=0.5$, the solution of the differential equation,$$t\frac{dx}{dt}+x=t$$ is$x=t-\frac{1}{2}$$x=t^2-\frac{1}{2}$$x=\frac{t^2}{2}$$x=\frac{t}{2}$...
Milicevic3306
16.0k
points
86
views
Milicevic3306
asked
Mar 25, 2018
Differential Equations
gate2012-ec
differential-equations
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–
0
votes
0
answers
51
GATE ECE 2012 | Question: 14
In the circuit shown $Y=\overline{A} \overline{B}+\bar{C}$ $Y=(A+B)C$ $Y=(\overline{A}+\overline{B})\overline{C}$ $Y=AB+C$
In the circuit shown$Y=\overline{A} \overline{B}+\bar{C}$$Y=(A+B)C$$Y=(\overline{A}+\overline{B})\overline{C}$$Y=AB+C$
Milicevic3306
16.0k
points
83
views
Milicevic3306
asked
Mar 25, 2018
Others
gate2012-ec
to-be-tagged
+
–
0
votes
0
answers
52
GATE ECE 2012 | Question: 13
The diodes and capacitors in the circuit shown are ideal. The voltage $v(t)$ across the diode $D1$ is $\cos(\omega t)-1$ $\sin(\omega t)$ $1-\cos(\omega t)$ $1-\sin(\omega t)$
The diodes and capacitors in the circuit shown are ideal. The voltage $v(t)$ across the diode $D1$ is$\cos(\omega t)-1$$\sin(\omega t)$$1-\cos(\omega t)$$1-\sin(\omega t)...
Milicevic3306
16.0k
points
94
views
Milicevic3306
asked
Mar 25, 2018
Analog Circuits
gate2012-ec
analog-circuits
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–
0
votes
0
answers
53
GATE ECE 2012 | Question: 16
A coaxial cable with an inner diameter of $1\:mm$ and outer diameter of $2.4\:mm$ is filled with a dielectric of relative permittivity $10.89$. Given $\mu_0=4\pi\times10^{-7}\:H/m$, $\varepsilon_0=\frac{10^{-9}}{36\pi}\:F/m$, the characteristic impedance of the cable is $330\:\Omega$ $100\:\Omega$ $143.3\:\Omega$ $43.4\:\Omega$
A coaxial cable with an inner diameter of $1\:mm$ and outer diameter of $2.4\:mm$ is filled with a dielectric of relative permittivity $10.89$. Given $\mu_0=4\pi\times10^...
Milicevic3306
16.0k
points
95
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
impedance
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–
0
votes
0
answers
54
GATE ECE 2012 | Question: 17
The radiation pattern of an antenna in spherical co-ordinates is given by $F(\theta)=\cos^4\theta\:\:\:;\:\:\:0\le \theta\le \frac{\pi}{2}$ The directivity of the antenna is $10\:dB$ $12.6\:dB$ $11.5\:dB$ $18\:dB$
The radiation pattern of an antenna in spherical co-ordinates is given by$$F(\theta)=\cos^4\theta\:\:\:;\:\:\:0\le \theta\le \frac{\pi}{2}$$The directivity of the antenna...
Milicevic3306
16.0k
points
75
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
antennas
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–
0
votes
0
answers
55
GATE ECE 2012 | Question: 6
Consider the given circuit. In the circuit, the race around does not occur occurs when $\text{CLK}=0$ occurs when $\text{CLK}=1$ and $A=B=1$ occurs when $\text{CLK}=1$ and $A=B=0$
Consider the given circuit.In the circuit, the race arounddoes not occuroccurs when $\text{CLK}=0$occurs when $\text{CLK}=1$ and $A=B=1$occurs when $\text{CLK}=1$ and $A=...
Milicevic3306
16.0k
points
150
views
Milicevic3306
asked
Mar 25, 2018
Number Representations
gate2012-ec
digital-circuits
sequential-circuit
flip-flop
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–
0
votes
0
answers
56
GATE ECE 2012 | Question: 8
The $i-v$ characteristics of the diode in the circuit given below are $i = \begin{cases} \frac{v-0.07}{500}\:A, & v\ge0.7\:V \\ \:\:\:\:\:\:\:\:0\:A, & v \lt 0.7\:V \end{cases}$ The current in the circuit is $10\:mA$ $9.3\:mA$ $6.67\:mA$ $6.2\:mA$
The $i-v$ characteristics of the diode in the circuit given below are$$i = \begin{cases} \frac{v-0.07}{500}\:A, & v\ge0.7\:V \\ \:\:\:\:\:\:\:\:0\:A, & v \lt 0.7\:V \en...
Milicevic3306
16.0k
points
118
views
Milicevic3306
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
carrier-transport
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–
0
votes
0
answers
57
GATE ECE 2012 | Question: 9
In the following figure, $C_1$ and $C_2$ are ideal capacitors. $C_1$ has been charged to $12\:V$ before the ideal switch $S$ is closed at $t=0$. The current $i(t)$ for all $t$ is zero a step function an exponentially decaying function an impulse function
In the following figure, $C_1$ and $C_2$ are ideal capacitors. $C_1$ has been charged to $12\:V$ before the ideal switch $S$ is closed at $t=0$. The current $i(t)$ for al...
Milicevic3306
16.0k
points
107
views
Milicevic3306
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
+
–
0
votes
0
answers
58
GATE ECE 2012 | Question: 11
The unilateral Laplace transform of $f(t)$ is $\frac{1}{s^2+s+1}$. The unilateral Laplace transform of $tf(t)$ is $-\frac{s}{(s^2+s+1)^2}$ $-\frac{2s+1}{(s^2+s+1)^2}$ $\frac{s}{(s^2+s+1)^2}$ $\frac{2s+1}{(s^2+s+1)^2}$
The unilateral Laplace transform of $f(t)$ is $\frac{1}{s^2+s+1}$. The unilateral Laplace transform of $tf(t)$ is$-\frac{s}{(s^2+s+1)^2}$$-\frac{2s+1}{(s^2+s+1)^2}$$\frac...
Milicevic3306
16.0k
points
138
views
Milicevic3306
asked
Mar 25, 2018
Network Solution Methods
gate2012-ec
network-solution-methods
laplace-transform
+
–
0
votes
0
answers
59
GATE ECE 2012 | Question: 5
The electric field of a uniform plane electromagnetic wave in free space, along the positive $x$ direction, is given by $\overrightarrow{E}=10(\hat{a}_y+j\hat{a}_z)e^{-j\:25x}$. The frequency and polarization of the wave, respectively, are $1.2\:GHz$ and left circular $4\:Hz$ and left circular $1.2\:GHz$ and right circular $4\:Hz$ and right circular
The electric field of a uniform plane electromagnetic wave in free space, along the positive $x$ direction, is given by $\overrightarrow{E}=10(\hat{a}_y+j\hat{a}_z)e^{-j\...
Milicevic3306
16.0k
points
156
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
+
–
0
votes
0
answers
60
GATE ECE 2012 | Question: 7
The output $Y$ of a $2-\text{bit}$ comparator is logic $1$ whenever the $2-\text{bit}$ input $A$ is greater than the $2-\text{bit}$ input $B$. The number of combinations for which the output is logic $1$, is $4$ $6$ $8$ $10$
The output $Y$ of a $2-\text{bit}$ comparator is logic $1$ whenever the $2-\text{bit}$ input $A$ is greater than the $2-\text{bit}$ input $B$. The number of combinations ...
Milicevic3306
16.0k
points
80
views
Milicevic3306
asked
Mar 25, 2018
Digital Circuits
gate2012-ec
digital-circuits
+
–
0
votes
0
answers
61
GATE ECE 2012 | Question: 10
The average power delivered to an impedance $(4-j3)\:\Omega$ by a current $5\cos(100\pi t+100)\:A$ is $44.2\:W$ $50\:W$ $62.5\:W$ $125\:W$
The average power delivered to an impedance $(4-j3)\:\Omega$ by a current $5\cos(100\pi t+100)\:A$ is$44.2\:W$$50\:W$$62.5\:W$$125\:W$
Milicevic3306
16.0k
points
70
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
impedance
+
–
0
votes
0
answers
62
GATE ECE 2012 | Question: 3
In a baseband communications link, frequencies upto $3500\:Hz$ are used for signaling. Using a raised cosine pulse with $75\%$ excess bandwidth and for no inter-symbol interference, the maximum possible signaling rate in the symbols per second is $1750$ $2625$ $4000$ $5250$
In a baseband communications link, frequencies upto $3500\:Hz$ are used for signaling. Using a raised cosine pulse with $75\%$ excess bandwidth and for no inter-symbol in...
Milicevic3306
16.0k
points
88
views
Milicevic3306
asked
Mar 25, 2018
Communications
gate2012-ec
communications
calculation-of-bandwidth
+
–
0
votes
0
answers
63
GATE ECE 2012 | Question: 2
The power spectral density of a real process $X(t)$ for positive frequencies is shown below. The values of $E[X^2(t)]$ and $ \mid E[X(t)] \mid$, respectively, are $\frac{6000}{\pi}\:,\:0$ $\frac{6400}{\pi}\:,\:0$ $\frac{6400}{\pi}\:,\:\frac{20}{(\pi\sqrt2)}$ $\frac{6000}{\pi}\:,\:\frac{20}{(\pi\sqrt2)}$
The power spectral density of a real process $X(t)$ for positive frequencies is shown below. The values of $E[X^2(t)]$ and $ \mid E[X(t)] \mid$, respectively, are$\frac{6...
Milicevic3306
16.0k
points
110
views
Milicevic3306
asked
Mar 25, 2018
Communications
gate2012-ec
communications
autocorrelation-and-power-spectral-density
+
–
0
votes
0
answers
64
GATE ECE 2012 | Question: 4
A plane wave propagating in air with $\overrightarrow{E}=(8\hat{a}_x+6\hat{a}_y+5\hat{a}_z)e^{j(\omega t+3x-4y)}\:V/m$ is incident on a perfectly conducting slab positioned at $x\le0$ . The $\overrightarrow{E}$ ... $(-8\hat{a}_x+6\hat{a}_y-5\hat{a}_z)e^{j(\omega t-3x-4y)}\:V/m$
A plane wave propagating in air with $\overrightarrow{E}=(8\hat{a}_x+6\hat{a}_y+5\hat{a}_z)e^{j(\omega t+3x-4y)}\:V/m$ is incident on a perfectly conducting slab position...
Milicevic3306
16.0k
points
128
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
propagation
+
–
0
votes
0
answers
65
GATE ECE 2012 | Question: 1
The current $i_b$ through the base of a silicon $npn$ transistor is $1+0.1\cos(10000\pi t)\:mA$. At $300\:K$, the $r_\pi$ in the small signal model of the transistor is $250\:\Omega$ $27.5\:\Omega$ $25\:\Omega$ $22.5\:\Omega$
The current $i_b$ through the base of a silicon $npn$ transistor is $1+0.1\cos(10000\pi t)\:mA$. At $300\:K$, the $r_\pi$ in the small signal model of the transistor is$2...
Milicevic3306
16.0k
points
106
views
Milicevic3306
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
intrinsic-and-extrinsic-silicon
+
–
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