Register
Filter

Recent questions without answers

1 votes
0 answers
1804
GATE ECE 2011 | Question: 40
The output of a $3$-stage Johnson (twisted-ring) counter is fed to a digital-to-analog (D/A) converter as shown in the figure below. Assume all states of the counter to be unset initially. The waveform which represents the D/A converter output $\mathrm{V}_{\mathrm{o}}$ is
The output of a $3$-stage Johnson (twisted-ring) counter is fed to a digital-to-analog (D/A) converter as shown in the figure below. Assume all states of the counter to b...
1 votes
0 answers
1807
GATE ECE 2011 | Question: 43
An input $\mathrm{x(t)}=\exp (-2 \mathrm{t)u(t})+\delta(\mathrm{t}-6)$ is applied to an LTI system with impulse response $\mathrm{h(t)=u(t})$. The output is $[1-\exp (-2 \mathrm{t)] u(t)+u(t}+6)$ $[1-\exp (-2 \mathrm{t)] u(t)+u(t}-6)$ $0.5[1-\exp (-2 \mathrm{t)] u(t)+u(t}+6)$ $0.5[1-\exp (-2 \mathrm{t)] u(t)+u(t}-6)$
An input $\mathrm{x(t)}=\exp (-2 \mathrm{t)u(t})+\delta(\mathrm{t}-6)$ is applied to an LTI system with impulse response $\mathrm{h(t)=u(t})$. The output is$[1-\exp (-2 \...
1 votes
0 answers
1809
GATE ECE 2011 | Question: 45
If $F(s)=L[f(t)]=\dfrac{2(s+1)}{s^2+4 s+7}$ then the initial and final values of $f(t)$ are respectively $0,2$ $2,0$ $0, 2 / 7$ $2 / 7,0$
If $F(s)=L[f(t)]=\dfrac{2(s+1)}{s^2+4 s+7}$ then the initial and final values of $f(t)$ are respectively$0,2$$2,0$$0, 2 / 7$$2 / 7,0$
1 votes
0 answers
1810
GATE ECE 2011 | Question: 46
In the circuit shown below, the current $\text{I}$ is equal to $1.4 \angle 0^{\circ} \; \mathrm{A}$ $2.0 \angle 0^{\circ} \; \mathrm{A}$ $2.8 \angle 0^{\circ} \; \mathrm{A}$ $3.2 \angle 0^{\circ} \; \mathrm{A}$
In the circuit shown below, the current $\text{I}$ is equal to$1.4 \angle 0^{\circ} \; \mathrm{A}$$2.0 \angle 0^{\circ} \; \mathrm{A}$$2.8 \angle 0^{\circ} \; \mathrm{A}$...
1 votes
0 answers
1811
GATE ECE 2011 | Question: 47
A numerical solution of the equation $f(x)=x+\sqrt{x}-3=0$ can be obtained using Newton-Raphson method. If the starting value is $x=2$ for the iteration, the value of $x$ that is to be used in the next step is $0.306$ $0.739$ $1.694$ $2.306$
A numerical solution of the equation $f(x)=x+\sqrt{x}-3=0$ can be obtained using Newton-Raphson method. If the starting value is $x=2$ for the iteration, the value of $x$...
1 votes
0 answers
1812
GATE ECE 2011 | Question: 48
The channel resistance of an $\text{N}$-channel $\text{JFET}$ shown in the figure below is $600 \; \Omega$ when the full channel thickness $\left(\mathrm{t}_{\mathrm{ch}}\right)$ of $10 \; \mu \mathrm{m}$ ... $480 \; \Omega$ $600 \; \Omega$ $750 \; \Omega$ $1000 \; \Omega$
The channel resistance of an $\text{N}$-channel $\text{JFET}$ shown in the figure below is $600 \; \Omega$ when the full channel thickness $\left(\mathrm{t}_{\mathrm{ch}}...
1 votes
0 answers
1814
GATE ECE 2011 | Question: 50
The input-output transfer function of a plant $H(s)=\frac{100}{s(s+10)^2}$. The plant is placed in a unity negative feedback configuration as shown in the figure below. The signal flow graph that DOES NOT model the plant $\operatorname{transfer~function~} H(s)$ is
The input-output transfer function of a plant $H(s)=\frac{100}{s(s+10)^2}$. The plant is placed in a unity negative feedback configuration as shown in the figure below.Th...
1 votes
0 answers
1815
GATE ECE 2011 | Question: 51
The input-output transfer function of a plant $H(s)=\frac{100}{s(s+10)^2}$. The plant is placed in a unity negative feedback configuration as shown in the figure below. The gain margin of the system under closed loop unity negative feedback is $0 \mathrm{~dB}$ $20 \mathrm{~dB}$ $26 \mathrm{~dB}$ $46 \mathrm{~dB}$
The input-output transfer function of a plant $H(s)=\frac{100}{s(s+10)^2}$. The plant is placed in a unity negative feedback configuration as shown in the figure below.Th...
1 votes
0 answers
1818
GATE ECE 2011 | Question: 54
In the circuit shown below, assume that the voltage drop across a forward biased diode is $0.7 \mathrm{~V}$. The thermal voltage $\mathrm{V}_{\mathrm{t}}=\mathrm{kT} / \mathrm{q}=25 \mathrm{mV}$ ... $1 \mathrm{~mA}$ $1.28 \mathrm{~mA}$ $1.5 \mathrm{~mA}$ $2 \mathrm{~mA}$
In the circuit shown below, assume that the voltage drop across a forward biased diode is $0.7 \mathrm{~V}$. The thermal voltage $\mathrm{V}_{\mathrm{t}}=\mathrm{kT} / \m...
1 votes
0 answers
1819
GATE ECE 2011 | Question: 55
In the circuit shown below, assume that the voltage drop across a forward biased diode is $0.7 \mathrm{~V}$. The thermal voltage $\mathrm{V}_{\mathrm{t}}=\mathrm{kT} / \mathrm{q}=25 \mathrm{mV}$ ... $2 \cos (\omega \mathrm{t}) \; \mathrm{mV}$ $22 \cos (\omega \mathrm{t}) \; \mathrm{mV}$
In the circuit shown below, assume that the voltage drop across a forward biased diode is $0.7 \mathrm{~V}$. The thermal voltage $\mathrm{V}_{\mathrm{t}}=\mathrm{kT} / \m...
1 votes
0 answers
1820
GATE ECE 2011 | Question: 56
The question below consists of a pair of related words followed by four pairs of words. Select the pair that best expresses the relation in the original pair: Gladiator : Arena dancer : stage commuter : train teacher : classroom lawyer : courtroom
The question below consists of a pair of related words followed by four pairs of words. Select the pair that best expresses the relation in the original pair:Gladiator : ...
1 votes
0 answers
1823
GATE ECE 2011 | Question: 59
Choose the word from the options given below that is most nearly opposite in meaning to the given word: Frequency periodicity rarity gradualness persistency
Choose the word from the options given below that is most nearly opposite in meaning to the given word:Frequencyperiodicityraritygradualnesspersistency
1 votes
0 answers
1828
GATE ECE 2011 | Question: 64
Given that $\mathrm{f(y})=|\mathrm{y}| / \mathrm{y},$ and $\mathrm{q}$ is any non-zero real number, the value of $|\mathrm{f}(\mathrm{q})-\mathrm{f}(-\mathrm{q})|$ is $0$ $-1$ $1$ $2$
Given that $\mathrm{f(y})=|\mathrm{y}| / \mathrm{y},$ and $\mathrm{q}$ is any non-zero real number, the value of $|\mathrm{f}(\mathrm{q})-\mathrm{f}(-\mathrm{q})|$ is$0$$...
1 votes
0 answers
1829
GATE ECE 2011 | Question: 65
The sum of $n$ terms of the series $4+44+444+\ldots .$ is $(4 / 81)\left[10^{n+1}-9 n-1\right]$ $(4 / 81)\left[10^{n-1}-9 n-1\right]$ $(4 / 81)\left[10^{n+1}-9 n-10\right]$ $(4 / 81)\left[10^{n}-9 n-10\right]$
The sum of $n$ terms of the series $4+44+444+\ldots .$ is $(4 / 81)\left[10^{n+1}-9 n-1\right]$$(4 / 81)\left[10^{n-1}-9 n-1\right]$$(4 / 81)\left[10^{n+1}-9 n-10\right]$...
0 votes
0 answers
1830
GATE ECE 2022 | Question: 1
Consider the two-dimensional vector field $\overrightarrow{\rm F}(x, y) = x \overrightarrow{i} + y \overrightarrow{j},$ where $\overrightarrow{i}$ and $\overrightarrow{j}$ denote the unit vectors along the $x - $axis and the $y - $ ... $0$ $1$ $8 + 2 \pi$ $ - 1$
Consider the two-dimensional vector field $\overrightarrow{\rm F}(x, y) = x \overrightarrow{i} + y \overrightarrow{j},$ where $\overrightarrow{i}$ and $\overrightarrow{j}...
0 votes
0 answers
1832
GATE ECE 2022 | Question: 3
The current $I$ in the circuit shown is ______________. $1.25 \times 10^{-3} \; \text{A}$ $0.75 \times 10^{-3} \; \text{A}$ $ – 0.5 \times 10^{-3} \; \text{A}$ $1.16 \times 10^{-3} \; \text{A}$
The current $I$ in the circuit shown is ______________.$1.25 \times 10^{-3} \; \text{A}$$0.75 \times 10^{-3} \; \text{A}$$ – 0.5 \times 10^{-3} \; \text{A}$$1.16 \times...
0 votes
0 answers
1833
GATE ECE 2022 | Question: 4
Consider the circuit shown in the figure. The current $I$ flowing through the $10 \; \Omega$ resistor is _____________. $1 \; \text{A}$ $0 \; \text{A}$ $0.1 \; \text{A}$ $ – 0.1 \; \text{A}$
Consider the circuit shown in the figure. The current $I$ flowing through the $10 \; \Omega$ resistor is _____________.$1 \; \text{A}$$0 \; \text{A}$$0.1 \; \text{A}$$ �...
0 votes
0 answers
1834
GATE ECE 2022 | Question: 5
The Fourier transform $X(j \omega)$ of the signal $x(t) = \frac{t}{(1+t^{2})^{2}}$ is ______________. $\frac{\pi}{2j} \omega e^{– |\omega|}$ $\frac{\pi}{2} \omega e^{– |\omega|}$ $\frac{\pi}{2j}e^{– |\omega|}$ $\frac{\pi}{2}e^{– |\omega|}$
The Fourier transform $X(j \omega)$ of the signal$$x(t) = \frac{t}{(1+t^{2})^{2}}$$is ______________.$\frac{\pi}{2j} \omega e^{– |\omega|}$$\frac{\pi}{2} \omega e^{– ...
Page: