1 1 vote The propagation delay of the $2 \times 1$ MUX shown in the circuit is $10 \mathrm{~ns}$. Consider the propagation delay of the inverter as $0 \mathrm{~ns}$. If $\text{S}$ is set to $1$ then the output $\text{Y}$ is $\_\_\_\_\_\_$. a square wave of frequency $100 \mathrm{MHz}$ a square wave of frequency $50 \mathrm{MHz}$ constant at $0$ constant at $1$ Digital Circuits gateece-2024 digital-circuits multiplexers + – admin 2.0k views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes 100 MHz for 1 signal and 100 MHz for other so total timeperiod double frequency reduced B Abhiral_Gupta answered Aug 5 Abhiral_Gupta comment Share Follow 0 reply Please log in or register to add a comment.
