GO Electronics
Login
Register
Dark Mode
Brightness
Profile
Edit Profile
Messages
My favorites
My Updates
Logout
Filter
No answer
No selected answer
No upvoted answer
Previous GATE
Featured
Recent questions without a selected answer
0
votes
0
answers
2841
GATE ECE 2012 | Question: 37
In the CMOS circuit shown, electron and hole mobilities are equal, and $M1$ and $M2$ are equally sized. The device $M1$ is in the linear region if $V_{in}\lt 1.875\:V$ $1.875\:V\lt V_{in}\lt 3.125\:V$ $V_{in}\gt 3.125\:V$ $0\lt V_{in}\lt 5\:V$
In the CMOS circuit shown, electron and hole mobilities are equal, and $M1$ and $M2$ are equally sized. The device $M1$ is in the linear region if$V_{in}\lt 1.875\:V$$1.8...
Milicevic3306
16.0k
points
83
views
Milicevic3306
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
cmos
+
–
0
votes
0
answers
2842
GATE ECE 2012 | Question: 38
A binary symmetric channel (BSC) has a transition probability of $\frac{1}{8}$. If the binary transmit symbol $X$ is such that $P(X=0)\:=\:\frac{9}{10}$, then the probability of error for an optimum receiver will be $\frac{7}{80}$ $\frac{63}{80}$ $\frac{9}{10}$ $\frac{1}{10}$
A binary symmetric channel (BSC) has a transition probability of $\frac{1}{8}$. If the binary transmit symbol $X$ is such that $P(X=0)\:=\:\frac{9}{10}$, then the probabi...
Milicevic3306
16.0k
points
239
views
Milicevic3306
asked
Mar 25, 2018
Probability and Statistics
gate2012-ec
probability-and-statistics
probability
+
–
0
votes
0
answers
2843
GATE ECE 2012 | Question: 39
The signal $m(t)$ as shown is applied both to a phase modulator (with $k_p$ as the phase constant) and a frequency modulator (with $k_f$ as the frequency constant) having the same carrier frequency. The ratio $\frac{k_p}{k_f}$ (in $rad/Hz$) for the same maximum phase deviation is $8\pi$ $4\pi$ $2\pi$ $\pi$
The signal $m(t)$ as shown is applied both to a phase modulator (with $k_p$ as the phase constant) and a frequency modulator (with $k_f$ as the frequency constant) having...
Milicevic3306
16.0k
points
150
views
Milicevic3306
asked
Mar 25, 2018
Communications
gate2012-ec
communications
frequency-modulation
+
–
0
votes
0
answers
2844
GATE ECE 2012 | Question: 40
The magnetic field along the propagation direction inside a rectangular waveguide with the cross-section shown in the figure is $H_Z=3\:\cos(2.094\times10^2x)\:\cos(2.618\times10^2y)\:\cos(6.283\times10^{10}t-\beta z)$ The phase velocity $v_p$ of the wave inside the waveguide satisfies $v_p\gt c$ $v_p=c$ $0\lt v_p\lt c$ $v_p=0$
The magnetic field along the propagation direction inside a rectangular waveguide with the cross-section shown in the figure is$$H_Z=3\:\cos(2.094\times10^2x)\:\cos(2.618...
Milicevic3306
16.0k
points
228
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
propagation
+
–
0
votes
0
answers
2845
GATE ECE 2012 | Question: 41
The circuit shown is a low pass filter with $f_{3\:dB}=\frac{1}{(R_1+R_2)C}\: rad/s$ high pass filter with $f_{3\:dB}=\frac{1}{R_1C}\: rad/s$ low pass filter with $f_{3\:dB}=\frac{1}{R_1C}\: rad/s$ high pass filter with $f_{3\:dB}=\frac{1}{(R_1+R_2)C}\: rad/s$
The circuit shown is a low pass filter with $f_{3\:dB}=\frac{1}{(R_1+R_2)C}\: rad/s$high pass filter with $f_{3\:dB}=\frac{1}{R_1C}\: rad/s$low pass filter with $f_{3\:dB...
Milicevic3306
16.0k
points
134
views
Milicevic3306
asked
Mar 25, 2018
Continuous-time Signals
gate2012-ec
continuous-time-signals
digital-filter-design-techniques
+
–
0
votes
0
answers
2846
GATE ECE 2012 | Question: 27
A BPSK scheme operating over an AWGN channel with noise power spectral density of $\frac{N_o}{2}$, uses equiprobable signals $s_1(t)=\sqrt{\frac{2E}{T}}\sin(\omega_ct)$ and $s_2(t)=-\sqrt{\frac{2E}{T}}\sin(\omega_ct)$ over the symbol interval $(0,T)$. If the local oscillator ... $Q(\sqrt{\frac{E}{N_o}})$ $Q(\sqrt{\frac{E}{2N_o}})$ $Q(\sqrt{\frac{E}{4N_o}})$
A BPSK scheme operating over an AWGN channel with noise power spectral density of $\frac{N_o}{2}$, uses equiprobable signals $s_1(t)=\sqrt{\frac{2E}{T}}\sin(\omega_ct)$ a...
Milicevic3306
16.0k
points
97
views
Milicevic3306
asked
Mar 25, 2018
Communications
gate2012-ec
communications
autocorrelation-and-power-spectral-density
+
–
0
votes
0
answers
2847
GATE ECE 2012 | Question: 28
A trasmission line with a characteristic impedance of $100\:\Omega$ is used to match a $50\:\Omega$ section to a $200\:\Omega$ section. If the matching is to be done both at $429\:MHz$ and $1\:GHz$, the length of the transmission line can be approximately $82.5\:cm$ $1.05\:m$ $1.58\:m$ $1.75\:m$
A trasmission line with a characteristic impedance of $100\:\Omega$ is used to match a $50\:\Omega$ section to a $200\:\Omega$ section. If the matching is to be done both...
Milicevic3306
16.0k
points
81
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
transmission-lines
+
–
0
votes
0
answers
2848
GATE ECE 2012 | Question: 29
The input $x(t)$ and output $y(t)$ of a system are related as $y(t)=\underset{-\infty}{\int}x(\tau)\cos(3\tau)d\tau$. The system is time-invariant and stable stable and not time-invariant time-invariant and not stable not time-invariant and not stable
The input $x(t)$ and output $y(t)$ of a system are related as $y(t)=\underset{-\infty}{\int}x(\tau)\cos(3\tau)d\tau$. The system istime-invariant and stablestable and not...
Milicevic3306
16.0k
points
82
views
Milicevic3306
asked
Mar 25, 2018
Analog Circuits
gate2012-ec
analog-circuits
+
–
0
votes
0
answers
2849
GATE ECE 2012 | Question: 30
The feedback system shown below oscillates at $2\:rad/s$ when $K=2$ and $a=0.75$ $K=3$ and $a=0.75$ $K=4$ and $a=0.5$ $K=2$ and $a=0.5$
The feedback system shown below oscillates at $2\:rad/s$ when$K=2$ and $a=0.75$$K=3$ and $a=0.75$$K=4$ and $a=0.5$$K=2$ and $a=0.5$
Milicevic3306
16.0k
points
91
views
Milicevic3306
asked
Mar 25, 2018
Analog Circuits
gate2012-ec
analog-circuits
oscillator
+
–
0
votes
0
answers
2850
GATE ECE 2012 | Question: 31
The Fourier transform of a signal $h(t)$ is $H(j\omega)=(2\cos\omega)(\sin2\omega)/\omega$. The value of $h(0)$ is $\frac{1}{4}$ $\frac{1}{2}$ $1$ $2$
The Fourier transform of a signal $h(t)$ is $H(j\omega)=(2\cos\omega)(\sin2\omega)/\omega$. The value of $h(0)$ is$\frac{1}{4}$$\frac{1}{2}$$1$$2$
Milicevic3306
16.0k
points
302
views
Milicevic3306
asked
Mar 25, 2018
Continuous-time Signals
gate2012-ec
continuous-time-signals
signals-and-systems
fourier-transform
+
–
0
votes
0
answers
2851
GATE ECE 2012 | Question: 32
The state variable description of an LTI system is given by ... $a_1\neq 0,a_2=0,a_3\neq 0$ $a_1=0,a_2\neq0,a_3\neq 0$ $a_1=0,a_2\neq0,a_3=0$ $a_1\neq 0,a_2\neq0,a_3=0$
The state variable description of an LTI system is given by$$\begin{pmatrix} \dot{x_1}\\ \dot{x_2}\\ \dot{x_3} \end{pmatrix}=\begin{pmatrix} 0 & a_1 & 0\\ 0 & 0 & a_2\\a_...
Milicevic3306
16.0k
points
514
views
Milicevic3306
asked
Mar 25, 2018
Continuous-time Signals
gate2012-ec
continuous-time-signals
signals-and-systems
linear-time-invariant-systems
+
–
0
votes
0
answers
2852
GATE ECE 2012 | Question: 33
Assuming both the voltage sources are in phase, the value of $R$ for which maximum power is transferred from circuit $A$ to circuit $B$ is $0.8\:\Omega$ $1.4\:\Omega$ $2\:\Omega$ $2.8\:\Omega$
Assuming both the voltage sources are in phase, the value of $R$ for which maximum power is transferred from circuit $A$ to circuit $B$ is$0.8\:\Omega$$1.4\:\Omega$$2\:\O...
Milicevic3306
16.0k
points
75
views
Milicevic3306
asked
Mar 25, 2018
Analog Circuits
gate2012-ec
analog-circuits
+
–
0
votes
0
answers
2853
GATE ECE 2012 | Question: 34
Consider the differential equation $\frac{d^2y(t)}{dt^2}+2\frac{dy(t)}{dt}+y(t)=\delta(t)$ with $y(t)\big|_{t=0^-}=-2$ and $\frac{dy}{dt}\big|_{t=0^-}=0$. The numerical value of $\frac{dy}{dt}\big|_{t=0^+}$ is $-2$ $-1$ $0$ $1$
Consider the differential equation$\frac{d^2y(t)}{dt^2}+2\frac{dy(t)}{dt}+y(t)=\delta(t)$ with $y(t)\big|_{t=0^-}=-2$ and $\frac{dy}{dt}\big|_{t=0^-}=0$.The numerical val...
Milicevic3306
16.0k
points
113
views
Milicevic3306
asked
Mar 25, 2018
Differential Equations
gate2012-ec
differential-equations
+
–
0
votes
0
answers
2854
GATE ECE 2012 | Question: 20
A system with transfer function $G(s)=\frac{(s^2+9)(s+2)}{(s+1)(s+3)(s+4)}$ is excited by $\sin(\omega t)$. The steady-state output of the system is zero at $\omega=1\:rad/s$ $\omega=2\:rad/s$ $\omega=3\:rad/s$ $\omega=4\:rad/s$
A system with transfer function$$G(s)=\frac{(s^2+9)(s+2)}{(s+1)(s+3)(s+4)}$$is excited by $\sin(\omega t)$. The steady-state output of the system is zero at$\omega=1\:rad...
Milicevic3306
16.0k
points
127
views
Milicevic3306
asked
Mar 25, 2018
Network Solution Methods
gate2012-ec
network-solution-methods
transfer-function
+
–
0
votes
0
answers
2855
GATE ECE 2012 | Question: 21
The impedance looking into nodes $1$ and $2$ in the given circuit is $50\:\Omega$ $100\:\Omega$ $5\:k\Omega$ $10.1\:k\Omega$
The impedance looking into nodes $1$ and $2$ in the given circuit is$50\:\Omega$$100\:\Omega$$5\:k\Omega$$10.1\:k\Omega$
Milicevic3306
16.0k
points
88
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
impedance
+
–
0
votes
0
answers
2856
GATE ECE 2012 | Question: 22
In the circuit shown below, the current through the inductor is $\frac{2}{1+j}\:A$ $\frac{-1}{1+j}\:A$ $\frac{1}{1+j}\:A$ $0\:A$
In the circuit shown below, the current through the inductor is$\frac{2}{1+j}\:A$$\frac{-1}{1+j}\:A$$\frac{1}{1+j}\:A$$0\:A$
Milicevic3306
16.0k
points
130
views
Milicevic3306
asked
Mar 25, 2018
Others
gate2012-ec
to-be-tagged
+
–
0
votes
0
answers
2857
GATE ECE 2012 | Question: 23
Given $f(z)=\frac{1}{z+1}-\frac{2}{z+3}$. If $C$ is a counterclockwise path in the z-plane such that $\mid z+1 \mid=1$, the value of $\frac{1}{2\pi j}\oint_cf(z)dz$ is $-2$ $-1$ $1$ $2$
Given $f(z)=\frac{1}{z+1}-\frac{2}{z+3}$. If $C$ is a counterclockwise path in the z-plane such that $\mid z+1 \mid=1$, the value of $\frac{1}{2\pi j}\oint_cf(z)dz$ is$-2...
Milicevic3306
16.0k
points
104
views
Milicevic3306
asked
Mar 25, 2018
Vector Analysis
gate2012-ec
vector-analysis
+
–
0
votes
0
answers
2858
GATE ECE 2012 | Question: 24
Two independent random variables $X$ and $Y$ are uniformly distributed in the interval $[-1,1]$. The probability that max$[X,Y]$ is less than $\frac{1}{2}$ is $\frac{3}{4}$ $\frac{9}{16}$ $\frac{1}{4}$ $\frac{2}{3}$
Two independent random variables $X$ and $Y$ are uniformly distributed in the interval $[-1,1]$. The probability that max$[X,Y]$ is less than $\frac{1}{2}$ is$\frac{3}{4}...
Milicevic3306
16.0k
points
101
views
Milicevic3306
asked
Mar 25, 2018
Probability and Statistics
gate2012-ec
probability-and-statistics
probability
independent-events
random-variable
+
–
0
votes
0
answers
2859
GATE ECE 2012 | Question: 25
If $x=\sqrt{-1}$, then the value of $x^x$ is $e^{\frac{-\pi}{2}}$ $e^{\frac{\pi}{2}}$ $x$ $1$
If $x=\sqrt{-1}$, then the value of $x^x$ is$e^{\frac{-\pi}{2}}$$e^{\frac{\pi}{2}}$$x$$1$
Milicevic3306
16.0k
points
85
views
Milicevic3306
asked
Mar 25, 2018
Calculus
gate2012-ec
calculus
+
–
0
votes
0
answers
2860
GATE ECE 2012 | Question: 26
The source of a silicon ($n_i=10^{10}\:per\:cm^3$) n-channel MOS transistor has an area of $1\:sq\:\mu m$ and a depth of $1\:\mu m$. If the dopant density in the source is $10^{19}/cm^3$, the number of holes in the source region with the above volume is approximately $10^7$ $100$ $10$ $0$
The source of a silicon ($n_i=10^{10}\:per\:cm^3$) n-channel MOS transistor has an area of $1\:sq\:\mu m$ and a depth of $1\:\mu m$. If the dopant density in the source i...
Milicevic3306
16.0k
points
85
views
Milicevic3306
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
silicon
+
–
0
votes
0
answers
2861
GATE ECE 2012 | Question: 12
With initial condition $x(1)=0.5$, the solution of the differential equation, $t\frac{dx}{dt}+x=t$ is $x=t-\frac{1}{2}$ $x=t^2-\frac{1}{2}$ $x=\frac{t^2}{2}$ $x=\frac{t}{2}$
With initial condition $x(1)=0.5$, the solution of the differential equation,$$t\frac{dx}{dt}+x=t$$ is$x=t-\frac{1}{2}$$x=t^2-\frac{1}{2}$$x=\frac{t^2}{2}$$x=\frac{t}{2}$...
Milicevic3306
16.0k
points
86
views
Milicevic3306
asked
Mar 25, 2018
Differential Equations
gate2012-ec
differential-equations
+
–
0
votes
0
answers
2862
GATE ECE 2012 | Question: 13
The diodes and capacitors in the circuit shown are ideal. The voltage $v(t)$ across the diode $D1$ is $\cos(\omega t)-1$ $\sin(\omega t)$ $1-\cos(\omega t)$ $1-\sin(\omega t)$
The diodes and capacitors in the circuit shown are ideal. The voltage $v(t)$ across the diode $D1$ is$\cos(\omega t)-1$$\sin(\omega t)$$1-\cos(\omega t)$$1-\sin(\omega t)...
Milicevic3306
16.0k
points
94
views
Milicevic3306
asked
Mar 25, 2018
Analog Circuits
gate2012-ec
analog-circuits
+
–
0
votes
0
answers
2863
GATE ECE 2012 | Question: 14
In the circuit shown $Y=\overline{A} \overline{B}+\bar{C}$ $Y=(A+B)C$ $Y=(\overline{A}+\overline{B})\overline{C}$ $Y=AB+C$
In the circuit shown$Y=\overline{A} \overline{B}+\bar{C}$$Y=(A+B)C$$Y=(\overline{A}+\overline{B})\overline{C}$$Y=AB+C$
Milicevic3306
16.0k
points
83
views
Milicevic3306
asked
Mar 25, 2018
Others
gate2012-ec
to-be-tagged
+
–
0
votes
0
answers
2864
GATE ECE 2012 | Question: 15
A source alphabet consists of $N$ symbols with the probability of the first two symbols being the same. A source encoder increases the probability of the first symbol by a small amount $\varepsilon$ and decreases that of the second by $\varepsilon$. After encoding, the entropy of the source increases remains the same increases only if $N=2$ decreases
A source alphabet consists of $N$ symbols with the probability of the first two symbols being the same. A source encoder increases the probability of the first symbol by ...
Milicevic3306
16.0k
points
172
views
Milicevic3306
asked
Mar 25, 2018
Probability and Statistics
gate2012-ec
probability-and-statistics
probability
+
–
0
votes
0
answers
2865
GATE ECE 2012 | Question: 16
A coaxial cable with an inner diameter of $1\:mm$ and outer diameter of $2.4\:mm$ is filled with a dielectric of relative permittivity $10.89$. Given $\mu_0=4\pi\times10^{-7}\:H/m$, $\varepsilon_0=\frac{10^{-9}}{36\pi}\:F/m$, the characteristic impedance of the cable is $330\:\Omega$ $100\:\Omega$ $143.3\:\Omega$ $43.4\:\Omega$
A coaxial cable with an inner diameter of $1\:mm$ and outer diameter of $2.4\:mm$ is filled with a dielectric of relative permittivity $10.89$. Given $\mu_0=4\pi\times10^...
Milicevic3306
16.0k
points
95
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
impedance
+
–
0
votes
0
answers
2866
GATE ECE 2012 | Question: 17
The radiation pattern of an antenna in spherical co-ordinates is given by $F(\theta)=\cos^4\theta\:\:\:;\:\:\:0\le \theta\le \frac{\pi}{2}$ The directivity of the antenna is $10\:dB$ $12.6\:dB$ $11.5\:dB$ $18\:dB$
The radiation pattern of an antenna in spherical co-ordinates is given by$$F(\theta)=\cos^4\theta\:\:\:;\:\:\:0\le \theta\le \frac{\pi}{2}$$The directivity of the antenna...
Milicevic3306
16.0k
points
75
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
antennas
+
–
0
votes
0
answers
2867
GATE ECE 2012 | Question: 18
If $x[n]=(\frac{1}{3})^{|n|}-(\frac{1}{2})^{|n|}u[n]$, then the region of convergence (ROC) of its Z-transform in the Z-plane will be $\frac{1}{3}\lt |z|\lt 3$ $\frac{1}{3}\lt |z|\lt \frac{1}{2}$ $\frac{1}{2}\lt |z|\lt 3$ $\frac{1}{3}\lt |z|$
If $x[n]=(\frac{1}{3})^{|n|}-(\frac{1}{2})^{|n|}u[n]$, then the region of convergence (ROC) of its Z-transform in the Z-plane will be$\frac{1}{3}\lt |z|\lt 3$$\frac{1}{3}...
Milicevic3306
16.0k
points
105
views
Milicevic3306
asked
Mar 25, 2018
Numerical Methods
gate2012-ec
numerical-methods
convergence-criteria
+
–
1
votes
0
answers
2868
GATE ECE 2012 | Question: 19
In the sum of products function $f(X,Y,Z)=\sum(2,3,4,5)$, the prime implicants are $\overline{X}Y,X\overline{Y}$ $\overline{X}Y,X\overline{Y}\;\overline{Z},X\overline{Y}Z$ $\overline{X}Y\overline{Z},\overline{X}YZ,X\overline{Y}$ $\overline{X}Y\overline{Z},\overline{X}YZ,X\overline{Y}\;\overline{Z},X\overline{Y}Z$
In the sum of products function $f(X,Y,Z)=\sum(2,3,4,5)$, the prime implicants are$\overline{X}Y,X\overline{Y}$$\overline{X}Y,X\overline{Y}\;\overline{Z},X\overline{Y}Z$$...
Milicevic3306
16.0k
points
155
views
Milicevic3306
asked
Mar 25, 2018
Number Representations
gate2012-ec
digital-circuits
boolean-algebra
+
–
0
votes
0
answers
2869
GATE ECE 2012 | Question: 5
The electric field of a uniform plane electromagnetic wave in free space, along the positive $x$ direction, is given by $\overrightarrow{E}=10(\hat{a}_y+j\hat{a}_z)e^{-j\:25x}$. The frequency and polarization of the wave, respectively, are $1.2\:GHz$ and left circular $4\:Hz$ and left circular $1.2\:GHz$ and right circular $4\:Hz$ and right circular
The electric field of a uniform plane electromagnetic wave in free space, along the positive $x$ direction, is given by $\overrightarrow{E}=10(\hat{a}_y+j\hat{a}_z)e^{-j\...
Milicevic3306
16.0k
points
156
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
+
–
0
votes
0
answers
2870
GATE ECE 2012 | Question: 6
Consider the given circuit. In the circuit, the race around does not occur occurs when $\text{CLK}=0$ occurs when $\text{CLK}=1$ and $A=B=1$ occurs when $\text{CLK}=1$ and $A=B=0$
Consider the given circuit.In the circuit, the race arounddoes not occuroccurs when $\text{CLK}=0$occurs when $\text{CLK}=1$ and $A=B=1$occurs when $\text{CLK}=1$ and $A=...
Milicevic3306
16.0k
points
150
views
Milicevic3306
asked
Mar 25, 2018
Number Representations
gate2012-ec
digital-circuits
sequential-circuit
flip-flop
+
–
0
votes
0
answers
2871
GATE ECE 2012 | Question: 7
The output $Y$ of a $2-\text{bit}$ comparator is logic $1$ whenever the $2-\text{bit}$ input $A$ is greater than the $2-\text{bit}$ input $B$. The number of combinations for which the output is logic $1$, is $4$ $6$ $8$ $10$
The output $Y$ of a $2-\text{bit}$ comparator is logic $1$ whenever the $2-\text{bit}$ input $A$ is greater than the $2-\text{bit}$ input $B$. The number of combinations ...
Milicevic3306
16.0k
points
80
views
Milicevic3306
asked
Mar 25, 2018
Digital Circuits
gate2012-ec
digital-circuits
+
–
0
votes
0
answers
2872
GATE ECE 2012 | Question: 8
The $i-v$ characteristics of the diode in the circuit given below are $i = \begin{cases} \frac{v-0.07}{500}\:A, & v\ge0.7\:V \\ \:\:\:\:\:\:\:\:0\:A, & v \lt 0.7\:V \end{cases}$ The current in the circuit is $10\:mA$ $9.3\:mA$ $6.67\:mA$ $6.2\:mA$
The $i-v$ characteristics of the diode in the circuit given below are$$i = \begin{cases} \frac{v-0.07}{500}\:A, & v\ge0.7\:V \\ \:\:\:\:\:\:\:\:0\:A, & v \lt 0.7\:V \en...
Milicevic3306
16.0k
points
118
views
Milicevic3306
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
carrier-transport
+
–
0
votes
0
answers
2873
GATE ECE 2012 | Question: 9
In the following figure, $C_1$ and $C_2$ are ideal capacitors. $C_1$ has been charged to $12\:V$ before the ideal switch $S$ is closed at $t=0$. The current $i(t)$ for all $t$ is zero a step function an exponentially decaying function an impulse function
In the following figure, $C_1$ and $C_2$ are ideal capacitors. $C_1$ has been charged to $12\:V$ before the ideal switch $S$ is closed at $t=0$. The current $i(t)$ for al...
Milicevic3306
16.0k
points
107
views
Milicevic3306
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
+
–
0
votes
0
answers
2874
GATE ECE 2012 | Question: 10
The average power delivered to an impedance $(4-j3)\:\Omega$ by a current $5\cos(100\pi t+100)\:A$ is $44.2\:W$ $50\:W$ $62.5\:W$ $125\:W$
The average power delivered to an impedance $(4-j3)\:\Omega$ by a current $5\cos(100\pi t+100)\:A$ is$44.2\:W$$50\:W$$62.5\:W$$125\:W$
Milicevic3306
16.0k
points
70
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
impedance
+
–
0
votes
0
answers
2875
GATE ECE 2012 | Question: 11
The unilateral Laplace transform of $f(t)$ is $\frac{1}{s^2+s+1}$. The unilateral Laplace transform of $tf(t)$ is $-\frac{s}{(s^2+s+1)^2}$ $-\frac{2s+1}{(s^2+s+1)^2}$ $\frac{s}{(s^2+s+1)^2}$ $\frac{2s+1}{(s^2+s+1)^2}$
The unilateral Laplace transform of $f(t)$ is $\frac{1}{s^2+s+1}$. The unilateral Laplace transform of $tf(t)$ is$-\frac{s}{(s^2+s+1)^2}$$-\frac{2s+1}{(s^2+s+1)^2}$$\frac...
Milicevic3306
16.0k
points
138
views
Milicevic3306
asked
Mar 25, 2018
Network Solution Methods
gate2012-ec
network-solution-methods
laplace-transform
+
–
0
votes
0
answers
2876
GATE ECE 2012 | Question: 2
The power spectral density of a real process $X(t)$ for positive frequencies is shown below. The values of $E[X^2(t)]$ and $ \mid E[X(t)] \mid$, respectively, are $\frac{6000}{\pi}\:,\:0$ $\frac{6400}{\pi}\:,\:0$ $\frac{6400}{\pi}\:,\:\frac{20}{(\pi\sqrt2)}$ $\frac{6000}{\pi}\:,\:\frac{20}{(\pi\sqrt2)}$
The power spectral density of a real process $X(t)$ for positive frequencies is shown below. The values of $E[X^2(t)]$ and $ \mid E[X(t)] \mid$, respectively, are$\frac{6...
Milicevic3306
16.0k
points
110
views
Milicevic3306
asked
Mar 25, 2018
Communications
gate2012-ec
communications
autocorrelation-and-power-spectral-density
+
–
0
votes
0
answers
2877
GATE ECE 2012 | Question: 3
In a baseband communications link, frequencies upto $3500\:Hz$ are used for signaling. Using a raised cosine pulse with $75\%$ excess bandwidth and for no inter-symbol interference, the maximum possible signaling rate in the symbols per second is $1750$ $2625$ $4000$ $5250$
In a baseband communications link, frequencies upto $3500\:Hz$ are used for signaling. Using a raised cosine pulse with $75\%$ excess bandwidth and for no inter-symbol in...
Milicevic3306
16.0k
points
88
views
Milicevic3306
asked
Mar 25, 2018
Communications
gate2012-ec
communications
calculation-of-bandwidth
+
–
0
votes
0
answers
2878
GATE ECE 2012 | Question: 4
A plane wave propagating in air with $\overrightarrow{E}=(8\hat{a}_x+6\hat{a}_y+5\hat{a}_z)e^{j(\omega t+3x-4y)}\:V/m$ is incident on a perfectly conducting slab positioned at $x\le0$ . The $\overrightarrow{E}$ ... $(-8\hat{a}_x+6\hat{a}_y-5\hat{a}_z)e^{j(\omega t-3x-4y)}\:V/m$
A plane wave propagating in air with $\overrightarrow{E}=(8\hat{a}_x+6\hat{a}_y+5\hat{a}_z)e^{j(\omega t+3x-4y)}\:V/m$ is incident on a perfectly conducting slab position...
Milicevic3306
16.0k
points
128
views
Milicevic3306
asked
Mar 25, 2018
Electromagnetics
gate2012-ec
electromagnetics
propagation
+
–
0
votes
0
answers
2879
GATE ECE 2012 | Question: 1
The current $i_b$ through the base of a silicon $npn$ transistor is $1+0.1\cos(10000\pi t)\:mA$. At $300\:K$, the $r_\pi$ in the small signal model of the transistor is $250\:\Omega$ $27.5\:\Omega$ $25\:\Omega$ $22.5\:\Omega$
The current $i_b$ through the base of a silicon $npn$ transistor is $1+0.1\cos(10000\pi t)\:mA$. At $300\:K$, the $r_\pi$ in the small signal model of the transistor is$2...
Milicevic3306
16.0k
points
106
views
Milicevic3306
asked
Mar 25, 2018
Electronic Devices
gate2012-ec
electronic-devices
intrinsic-and-extrinsic-silicon
+
–
0
votes
1
answer
2880
GATE ECE 2018 | GA Question: 5
A $1.5$ m tall person is standing at a distance of $3$ m from a lamp post. The light from the lamp at the top of the post casts her shadow. The length of the shadow is twice her height. What is the height of the lamp post in meters? $1.5$ $3$ $4.5$ $6$
A $1.5$ m tall person is standing at a distance of $3$ m from a lamp post. The light from the lamp at the top of the post casts her shadow. The length of the shadow is tw...
gatecse
1.6k
points
271
views
gatecse
asked
Feb 19, 2018
Quantitative Aptitude
gate2018-ec
numerical-ability
geometry
+
–
Page:
« prev
1
...
69
70
71
72
73
74
75
...
78
next »
GO Electronics
Email or Username
Show
Hide
Password
I forgot my password
Remember
Log in
Register