2 2 votes In the sum of products function $f(X,Y,Z)=\sum(2,3,4,5)$, the prime implicants are $\overline{X}Y,X\overline{Y}$ $\overline{X}Y,X\overline{Y}\;\overline{Z},X\overline{Y}Z$ $\overline{X}Y\overline{Z},\overline{X}YZ,X\overline{Y}$ $\overline{X}Y\overline{Z},\overline{X}YZ,X\overline{Y}\;\overline{Z},X\overline{Y}Z$ Number Representations gate2012-ec digital-circuits boolean-algebra + – Milicevic3306 761 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
1 1 vote Answer is option $\boxed{A}$ Important Definitions : (source) https://cseweb.ucsd.edu/classes/sp14/cse140-b/slides/140-sp14-lec4.pdf Deepak Poonia answered Feb 1 Deepak Poonia comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Option A - 2 Prime implicants Binit_Gudhka answered Jun 22, 2025 Binit_Gudhka comment Share Follow 0 reply Please log in or register to add a comment.